(4) Determine ID in this circuit if VDs = 1V. . SHOW YOUR WORK. 3kQ 10V V₁ = 0.5V kn' = 0.5mA/V² W/L = 10 10V + TOM RD O 0 mA (in cutoff) O 45 mA O 226 mA O 45 A other/none of the above
(4) Determine ID in this circuit if VDs = 1V. . SHOW YOUR WORK. 3kQ 10V V₁ = 0.5V kn' = 0.5mA/V² W/L = 10 10V + TOM RD O 0 mA (in cutoff) O 45 mA O 226 mA O 45 A other/none of the above
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Question
![(4)
Determine ID in this circuit if VDs = 1V. . SHOW YOUR WORK.
3kQ
10V
M
V₁ = 0.5V
kn' = 0.5mA/V²
W/L = 10
10V
TOM
2
RD
O 0 mA (in cutoff)
O 45 mA
O 226 MA
O
45 A
O
other/none of the above](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8b5d3f26-cda5-43e5-8223-bfa02258241c%2Fefb718f8-823f-47ad-9e7c-ae494b3ce9a5%2F92nfnbk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(4)
Determine ID in this circuit if VDs = 1V. . SHOW YOUR WORK.
3kQ
10V
M
V₁ = 0.5V
kn' = 0.5mA/V²
W/L = 10
10V
TOM
2
RD
O 0 mA (in cutoff)
O 45 mA
O 226 MA
O
45 A
O
other/none of the above
Expert Solution
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Step 1: Concept
From the circuit:
VGS= 10V
VT= 0.5V
VDS= 1V.
Clearly VDS< VGS-VT
Hence transistor is operating in triode region
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Solved in 3 steps
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