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4) Consider the pka for the a) What is the pka of ammonia/ammonium ammonia/ammonium based off your data? weak base/conjugate acid pair. Page 3 of 5 Use Equation editor here to show all your work! You can copy and paste these when you need more lines pka of ammonium based on data Put your answer here!

4) Consider the pka for the a) What is the pka of ammonia/ammonium ammonia/ammonium based off your data? weak base/conjugate acid pair. Page 3 of 5 Use Equation editor here to show all your work! You can copy and paste these when you need more lines pka of ammonium based on data Put your answer here!

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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4) Consider the pka for the a) What is the pKa of ammonia/ammonium weak base/conjugate acid pair. ammonia/ammonium based off your data? Page 3 of 5 Use Equation editor here to show all your work! You can copy and paste these when you need more lines pka of ammonium based on data Put your answer here!
Transcribed Image Text:4) Consider the pka for the a) What is the pKa of ammonia/ammonium weak base/conjugate acid pair. ammonia/ammonium based off your data? Page 3 of 5 Use Equation editor here to show all your work! You can copy and paste these when you need more lines pka of ammonium based on data Put your answer here!
The sigmoidal curve observes for a combination of weak acids and strong bases or strong acids and weak bases. Because, no sharp neutralization point is possible here. So, to find out, equivalence point we need to take the "almost straight line" from S- shape. Step2 b) "Almost straight line" starts at 2.78 and finishes at 7.14. The exact value for the equivalence point will be the midpoint of these two points for S-shaped graph. So, it would be= (2.78+7.14)/2=4.96. Step3 c) This point is close to 5.01 on the graph. The equivalence point is =5.01 Step4 d) Half equivalence point will be=5.01/2=2.50, from the graph, the equivalence point will be 2.78, so pH at that point is=4 We are taking the closest point that matches with the graph, as it will give us an idea about the correct pH.
Transcribed Image Text:The sigmoidal curve observes for a combination of weak acids and strong bases or strong acids and weak bases. Because, no sharp neutralization point is possible here. So, to find out, equivalence point we need to take the "almost straight line" from S- shape. Step2 b) "Almost straight line" starts at 2.78 and finishes at 7.14. The exact value for the equivalence point will be the midpoint of these two points for S-shaped graph. So, it would be= (2.78+7.14)/2=4.96. Step3 c) This point is close to 5.01 on the graph. The equivalence point is =5.01 Step4 d) Half equivalence point will be=5.01/2=2.50, from the graph, the equivalence point will be 2.78, so pH at that point is=4 We are taking the closest point that matches with the graph, as it will give us an idea about the correct pH.
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