4- chapter24-question1 Determine the electric flux passing through the right-angled isosceles triangle with equal sides being a=10 cm as shown in the figure. The point charge dA (q=8.85 nC) is perpendicularly below the triangle plane at a distance a=10 cm from one of its 45 degree vertices (corner), in N m²/C (Hint: Consider symmetry and Gauss's Law, E = 8.85 x 10-12 C² /N · m²) VZa Option1 Option2 Option3 Option4 Option5 20.8 81 74.5 61.0 8.8 a) Option1 b) Option3 C) Option2 d) Option4 e) Option5 Boş bırak COnceki 4/20 Sonraki> Карat

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4- chapter24-question1
Determine the electric flux passing through the right-angled isosceles triangle
with equal sides being a=10 cm as shown in the figure. The point charge
dA
(q=8.85 nC) is perpendicularly below the triangle plane at a distance a=10 cm
from one of its 45 degree vertices (corner), in N m²/C (Hint: Consider
symmetry and Gauss's Law, E = 8.85 x 10-12 C² /N · m²)
VZa
Option1 Option2 Option3 Option4 Option5
20.8
81
74.5
61.0
8.8
a)
Option1
b)
Option3
C)
Option2
d)
Option4
e)
Option5
Boş bırak
COnceki
4/20
Sonraki>
Карat
Transcribed Image Text:4- chapter24-question1 Determine the electric flux passing through the right-angled isosceles triangle with equal sides being a=10 cm as shown in the figure. The point charge dA (q=8.85 nC) is perpendicularly below the triangle plane at a distance a=10 cm from one of its 45 degree vertices (corner), in N m²/C (Hint: Consider symmetry and Gauss's Law, E = 8.85 x 10-12 C² /N · m²) VZa Option1 Option2 Option3 Option4 Option5 20.8 81 74.5 61.0 8.8 a) Option1 b) Option3 C) Option2 d) Option4 e) Option5 Boş bırak COnceki 4/20 Sonraki> Карat
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