4- Assume that we have two machines named as 1 and 2 producing part 1 and 2, respectively. In each sample, the weigh of parts are observed. Eleven parts are taken from part 1 and ten pieces are taken from part 2. The samples of part 1 gives an average of 85 grams with a sample standard deviation of 9, whereas the samples of part 2 gives an average of 81 with a sample standard deviation of 5. We want to test that whether there is a difference between two

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4- Assume that we have two machines named as 1 and 2 producing part 1 and 2, respectively. In
each sample, the weigh of parts are observed. Eleven parts are taken from part 1 and ten
pieces are taken from part 2. The samples of part 1 gives an average of 85 grams with a sample
standard deviation of 9, whereas the samples of part 2 gives an average of 81 with a sample
standard deviation of 5. We want to test that whether there is a difference between two
population variances. Use a 0.10 level of significance.
Transcribed Image Text:4- Assume that we have two machines named as 1 and 2 producing part 1 and 2, respectively. In each sample, the weigh of parts are observed. Eleven parts are taken from part 1 and ten pieces are taken from part 2. The samples of part 1 gives an average of 85 grams with a sample standard deviation of 9, whereas the samples of part 2 gives an average of 81 with a sample standard deviation of 5. We want to test that whether there is a difference between two population variances. Use a 0.10 level of significance.
a)
Hypothesis: H_0: o} = o3 ; H_1: o} > o;: Result: Reject H_0
b)
Hypothesis: H_0: oi = o3; H_1: o; + o ; Result: Reject H_0
H2; H_1: µ1 # µ2 ; Result: Fail to reject H_0
Hypothesis: H_0: o? = o3; H_1: o? to3; Result: Fail to reject H_0
02; H_1: 01 7 02; Result: Reject H_0
Hypothesis: H_0: µ1
Hypothesis: H_0: 01
Transcribed Image Text:a) Hypothesis: H_0: o} = o3 ; H_1: o} > o;: Result: Reject H_0 b) Hypothesis: H_0: oi = o3; H_1: o; + o ; Result: Reject H_0 H2; H_1: µ1 # µ2 ; Result: Fail to reject H_0 Hypothesis: H_0: o? = o3; H_1: o? to3; Result: Fail to reject H_0 02; H_1: 01 7 02; Result: Reject H_0 Hypothesis: H_0: µ1 Hypothesis: H_0: 01
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