SheetThickness10.040320.069330.063240.065150.053460.057470.040080.051590.0542100.0555110.0512120.0525130.0434140.0392150.0607160.0575170.0637180.0358190.0455200.0319210.0578220.0488230.0402240.0318250.0447260.0306270.0325280.0542290.0416300.0517310.0448320.0520330.0495340.0525350.0618360.0571370.0391380.0655390.0568400.0370410.0505420.0425430.0611440.0491450.0574460.0603470.0420480.0616490.0463500.0340510.0609520.0457530.0409540.0367550.0713560.0576570.0515580.0549590.0325600.0470610.0203620.0379630.0442640.0384650.0409660.0358670.0442680.0538690.0486700.0317710.0529720.0449730.0437740.0384750.0400760.0397770.0486780.0296790.0548800.0407810.0552820.0412830.0425840.0371850.0590860.0398870.0600880.0589890.0496900.0509910.0427920.0481930.0512940.0504950.0467960.0253970.0195980.0471990.04641000.0529 4) An aircraft manufacturer needs to buy aluminum sheets with an average thickness of 0.05inch. The manufacturer knows that significantly thinner sheets would be unsafe andconsiderably thicker sheets would be too heavy. A random sample of 100 sheets from apotential supplier is collected. The thickness for each sheet in this sample is measured (ininches) and the data appears in the Thickness worksheet of the W9 Hypothesis Test HWdata workbook on Moodle.a) What is the appropriate null and alternate hypothesis to conclude the averagethickness is less than 0.05?b) Use JMP to test the hypothesis of part a).c) Using a = 0.05, draw a conclusion for the hypothesis test. Make sure you state yourconclusion in the context of the problem.d) Using this data, what is the smallest value that you can conclude the average thicknessis less than at a = 0.05?

As per guidelines we will solve the first question only, please repost other questions for more…

Answered: 4) An aircraft manufacturer needs to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A new industrial oven has just been installed at Piatt Bakery. To develop experience regarding the oven temperature, an inspector reads the temperature at four different places inside the oven each half hour starting at 8:00 a.m. The last reading was at 10:30 a.m., for a total of six samples. The first reading, taken at 8:00 a.m., was 340 degrees Fahrenheit. (Only the last two digits are given in the following table to make the computations easier.) Time 8:00 a.m. 8:30 a.m. 9:00 a.m. 9:30 a.m. 10:00 a.m. 10:30 a.m. 1 40 44 41 39 37 39 Reading 2 50 42 45 39 42 40 3 55 38 47 41 46 39 Click here for the Excel Data File 4 39 38 43 41 41 40
7/8/22, 3:04 PM Area z TABLE V z 78877 99737 77238 23927 328797 97979 777738=283 09898 30003 99999 33233 38539 22 -3.4 -2.5 -0.5 0.0010 0.0013 .00 .01 .02 .06 .07 .08 .09 0.0007 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0003 0.0002 0.0005 0.0005 0.0005 0.0004 0.0004 0.0004 0.0004 0.0004 0.0004 0.0003 0.0007 0.0006 0.0006 0.0006 0.0006 0.0006 0.0005 0.0005 0.0005 0.0009 0.0009 0.0009 0.0008 0.0008 0.0008 0.0008 0.0007 0.0007 0.0013 0.0013 0.0012 0.0012 0.0011 0.0011 0.0011 0.0010 0.0010 0.0019 0.0018 0.0018 0.0017 0.0016 0.0016 0.0015 0.0015 0.0014 0.0014 0.0026 0.0025 0.0024 0.0023 0.0023 0.0022 0.0021 0.0021 0.0020 0.0019 0.0035 0.0034 0.0033 0.0032 0.0031 0.0030 0.0029 0.0028 0.0027 0.0026 0.0047 0.0045 0.0044 0.0043 0.0041 0.0040 0.0039 0.0038 0.0037 0.0036 0.0062 0.0060 0.0059 0.0057 0.0055 0.0054 0.0052 0.0051 0.0049 0.0048 0.0082 0.0080 0.0078 0.0075 0.0073 0.0071 0.0069 0.0068 0.0066 0.0064 0.0107 0.0104 0.0102 0.0099 0.0096 0.0094 0.0091 0.0089 0.0087 0.0084…
M means median
Question 8
You may need to use the appropriate appendix table or technology to answer this question. For at distribution with 16 degrees of freedom, find the area, or probability, in each region. (Round your answers to three decimal places. (a) to the right of 2.120 Enter a number. (b) to the left of 1.746 (c) to the left of -2.583 (d) to the right of 1.337 (e) between -2.120 and 2.120 (f) between -2.583 and 2.583
3.273525429 3.725058267 3.193881287 3.380595777 3.849062312 2.688788698 4.521501366 2.876926464 3.202865171 3.760862809 3.648737967 3.155042169 3.047772295 2.331491399 2.43426651 3.316262576 3.33570391 3.123784316 1.983014564 4.026381813 2.819851735 3.020835161 3.963952045 3.434812572 2.530150764 3.501124236 2.723868073 3.734018756 3.07485433 2.945439985 2.963046282 3.301251136 3.806637216 2.495620331 2.99022362 2.548798319 2.849586988 3.554039618 3.565046584 3.383944772 2.895875003 3.96006813 3.744978387 4.034873151 3.394484477 4.637022161 3.085000083 3.945715143 2.590540526 3.593019815 Data from sheet 5
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Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true standard deviation 0.72. (c) How large a sample size is necessary if the width of the 95% interval is to be 0.45? (Round your answer up to the nearest whole number.) ................ specimens(d) What sample size is necessary to estimate true average porosity to within 0.24 with 99% confidence? (Round your answer up to the nearest whole number.) ................. specimens

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Sheet	Thickness
1	0.0403
2	0.0693
3	0.0632
4	0.0651
5	0.0534
6	0.0574
7	0.0400
8	0.0515
9	0.0542
10	0.0555
11	0.0512
12	0.0525
13	0.0434
14	0.0392
15	0.0607
16	0.0575
17	0.0637
18	0.0358
19	0.0455
20	0.0319
21	0.0578
22	0.0488
23	0.0402
24	0.0318
25	0.0447
26	0.0306
27	0.0325
28	0.0542
29	0.0416
30	0.0517
31	0.0448
32	0.0520
33	0.0495
34	0.0525
35	0.0618
36	0.0571
37	0.0391
38	0.0655
39	0.0568
40	0.0370
41	0.0505
42	0.0425
43	0.0611
44	0.0491
45	0.0574
46	0.0603
47	0.0420
48	0.0616
49	0.0463
50	0.0340
51	0.0609
52	0.0457
53	0.0409
54	0.0367
55	0.0713
56	0.0576
57	0.0515
58	0.0549
59	0.0325
60	0.0470
61	0.0203
62	0.0379
63	0.0442
64	0.0384
65	0.0409
66	0.0358
67	0.0442
68	0.0538
69	0.0486
70	0.0317
71	0.0529
72	0.0449
73	0.0437
74	0.0384
75	0.0400
76	0.0397
77	0.0486
78	0.0296
79	0.0548
80	0.0407
81	0.0552
82	0.0412
83	0.0425
84	0.0371
85	0.0590
86	0.0398
87	0.0600
88	0.0589
89	0.0496
90	0.0509
91	0.0427
92	0.0481
93	0.0512
94	0.0504
95	0.0467
96	0.0253
97	0.0195
98	0.0471
99	0.0464
100	0.0529