4) A vibrating string, like on a guitar, often takes the form of e*sin(x). a) Graph this function to try to decide the value of lim e-*sin(x) We can use "The Squecze Theorem" to prove your result. -1< sin(x) < 1, so -e* se-* sin(x) se* b) Let's find the limits of the two squeezing functions. lim -e-* = lim e 00-X c) Are they the same? If they are, then they tell you the limit of the middle function lim e¯*sin(x).
4) A vibrating string, like on a guitar, often takes the form of e*sin(x). a) Graph this function to try to decide the value of lim e-*sin(x) We can use "The Squecze Theorem" to prove your result. -1< sin(x) < 1, so -e* se-* sin(x) se* b) Let's find the limits of the two squeezing functions. lim -e-* = lim e 00-X c) Are they the same? If they are, then they tell you the limit of the middle function lim e¯*sin(x).
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![4) A vibrating string, like on a guitar, often takes the form of e*sin(x).
a) Graph this function to try to decide the value of lim e-*sin(x)
We can use "The Squeeze Theorem" to prove your result. –1< sin(x) < 1, so
-e-* se-* sin(x) se*
b) Let's find the limits of the two squeezing functions.
lim -e-X =
lim eX =
X00
c) Are they the same? If they are, then they tell you the limit of the middle function lim e¯*sin(x).
Let's turn our attention to finding the derivative at a point.
The definition is f'(a) = lim (a+h)-/(@)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1eae7f78-6e9d-4eda-beea-751870032aa0%2Fd0bdade8-a69e-4f22-9f63-c7ffb60bb6ee%2F9nffylj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4) A vibrating string, like on a guitar, often takes the form of e*sin(x).
a) Graph this function to try to decide the value of lim e-*sin(x)
We can use "The Squeeze Theorem" to prove your result. –1< sin(x) < 1, so
-e-* se-* sin(x) se*
b) Let's find the limits of the two squeezing functions.
lim -e-X =
lim eX =
X00
c) Are they the same? If they are, then they tell you the limit of the middle function lim e¯*sin(x).
Let's turn our attention to finding the derivative at a point.
The definition is f'(a) = lim (a+h)-/(@)
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