4- A trunnion of diameter 12.363" has to be cooled from a room temperature of 80°F before it is shrink fit into a steel hub. The equation that gives the diametric contraction, in inches of the trunnion in dry-ice/alcohol (boiling temperature is - 108°F) is given by: -108 AD = 12.363 [ (-1.2278 × 10-1"7² + 6.1946× 10°T +6.015×10“ dT Use two segment Trapezoidal rule to find the contraction.
4- A trunnion of diameter 12.363" has to be cooled from a room temperature of 80°F before it is shrink fit into a steel hub. The equation that gives the diametric contraction, in inches of the trunnion in dry-ice/alcohol (boiling temperature is - 108°F) is given by: -108 AD = 12.363 [ (-1.2278 × 10-1"7² + 6.1946× 10°T +6.015×10“ dT Use two segment Trapezoidal rule to find the contraction.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![4- A trunnion of diameter 12.363" has to be cooled from a room temperature of 80°F
before it is shrink fit into a steel hub. The equation that gives the diametric contraction,
in inches of the trunnion in dry-ice/alcohol (boiling temperature is -108°F) is given by:
-108
AD = 12.363 ((-1.2278 × 10-"T² +6.1946 × 10°T + 6.015× 10“ dT
80
Use two segment Trapezoidal rule to find the contraction.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc6bada4f-cebd-42a4-bd1f-8c5a5e208222%2F45317d38-4dc1-4cda-9f12-85fc31b68a82%2F13seyo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4- A trunnion of diameter 12.363" has to be cooled from a room temperature of 80°F
before it is shrink fit into a steel hub. The equation that gives the diametric contraction,
in inches of the trunnion in dry-ice/alcohol (boiling temperature is -108°F) is given by:
-108
AD = 12.363 ((-1.2278 × 10-"T² +6.1946 × 10°T + 6.015× 10“ dT
80
Use two segment Trapezoidal rule to find the contraction.
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