4) A toy wood block of mass m1= 3.25 kg is pushed by hand to compress a spring with a spring constantk= 550 N/m a distance As = 25cm. The toy block is released by the hand and the spring launches the toyblock across a frictionless surface toward a more massive wood block ofimass m2= 5.0 kg. The 3.5 kgwood block is moving with an unkown velocity right before it collides with the more massive wood blockwhich is at rest. After the collision, the 5.0 kg block is moving to the right with a velocity of 3 m/s. The moremassive 5.0 kg block encounters a long rough section of surface having a coefficient of kinetic uk=0.22 andis eventually brought to rest.a) Find the velocity of the 3.25 kg block just before the collision.b) Find the velocity of the 3.25 kg block just after the collisionc) What is the system's energy just before the collision?d) What is the system's energy just after the collision?e) Is this collision, elastic, completely inelastic, or inelastic?f) What is the friction force on the 5.0 kg block when it is moving across the rough surface?g) How far will the 5.0 kg block slide across the rough surface before it comes to rest?k= ?0000As=

Name: 4) A toy wood block of mass m1= 3.25 kg is pushed by hand to compress
Uploaded: 2024-03-20T06:56:55.000Z
Channel: Bartleby
Description: 4) A toy wood block of mass m1= 3.25 kg is pushed by hand to compress a spring with a spring constantk= 550 N/m a distance As = 25cm. The toy block is released by the hand and the spring launches the toyblock across a frictionless surface toward a m

Solving first 3 sub questions Part aAccording to the given conditionThe energy possessed by spring system isE=12kx2E=0.5×550×0.25E=34.38 N.mnow the same energy is transfered to 3.25kg blockthus as it possess kinetic energy It is given asE=12mv1234.38=0.5×3.25×v12v1=4.6 m/sthus the velocity of block 1 before collision is 1.41 m/sPart bNow we have conservation of momentum principleapplying thatm1u1+m2u2=m1v1+m2v23.25×4.6+5×0=3.25v1+5×314.95=3.25v1+15v1≈0 m/sPart cAs per given above the energy of the system isE=34.38 N.m