4) A circuit in Figure consists of paralel-plate capacitors with and without dielectrics. Dielectric constants are K, = 2 and K, = 4. Parallel-plates have the area A = 0.8 m². The distance is d = 0.2 m. A potential difference of AV = 24 V is applied to the circuit. (a) Find the equivalent capacitance of the system. (b) Find the potential AV1. (E=8.85×10-12 C²/N×m²) d. d. K1 d d AV1 AV = 24 V

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4) A circuit in Figure consists of paralel-plate capacitors with and without dielectrics. Dielectric
constants are K,=2 and K, = 4. Parallel-plates have the area A = 0.8 m². The distance is d= 0.2 m.
A potential difference of AV = 24 V is applied to the circuit.
(a) Find the equivalent capacitance of the system.
(b) Find the potential AV1. (E,=8.85×10-12 C²/N×m²)
%3D
А
K2
d
THE
А
AV1
AV
= 24 V
Transcribed Image Text:4) A circuit in Figure consists of paralel-plate capacitors with and without dielectrics. Dielectric constants are K,=2 and K, = 4. Parallel-plates have the area A = 0.8 m². The distance is d= 0.2 m. A potential difference of AV = 24 V is applied to the circuit. (a) Find the equivalent capacitance of the system. (b) Find the potential AV1. (E,=8.85×10-12 C²/N×m²) %3D А K2 d THE А AV1 AV = 24 V
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