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4-9 A mass of 5 kg of saturated water vapor at 150 kPa is heated at constant pressure until the temperature reaches 200°C. Calculate the work done by the steam during this pro- cess. Answer: 214 kJ

4-9 A mass of 5 kg of saturated water vapor at 150 kPa is heated at constant pressure until the temperature reaches 200°C. Calculate the work done by the steam during this pro- cess. Answer: 214 kJ

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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From the Table (A-4 through A-6), obtain the value of specific volume at the initial and the final states. At initial pressure saturated vapour of 150 kPa 150   kPa . v 1 = v g @ 150 kPa = 1.15942 m 3 / kg v 1 = v g @ 150   kPa = 1.15942   m 3 / kg At final pressure and temperature of 150 kPa 150   kPa and 200 ° C 200 ° C . v 2 = 1.44449 m 3 / kg. I can’t find those values in the table.
**Problem 4-9: Thermodynamics** A mass of 5 kg of saturated water vapor at 150 kPa is heated at constant pressure until the temperature reaches 200°C. Calculate the work done by the steam during this process. **Answer: 214 kJ** This problem requires an understanding of the principles of thermodynamics, specifically relating to the behavior of saturated water vapor under pressure and temperature changes. The key here is to use the relationship between pressure, temperature, and work done in a thermodynamic system. To solve such a problem, you typically refer to steam tables or Mollier diagrams to determine specific properties of the steam at the given pressures and temperatures, such as specific volume. The work done can be calculated using the formula: \[ W = P \times (V_2 - V_1) \] Where: - \( W \) is the work done - \( P \) is the constant pressure - \( V_1 \) and \( V_2 \) are the initial and final specific volumes In this particular problem, after performing the necessary calculations and consulting appropriate tables, the work done by the steam is determined to be 214 kJ.
Transcribed Image Text:**Problem 4-9: Thermodynamics** A mass of 5 kg of saturated water vapor at 150 kPa is heated at constant pressure until the temperature reaches 200°C. Calculate the work done by the steam during this process. **Answer: 214 kJ** This problem requires an understanding of the principles of thermodynamics, specifically relating to the behavior of saturated water vapor under pressure and temperature changes. The key here is to use the relationship between pressure, temperature, and work done in a thermodynamic system. To solve such a problem, you typically refer to steam tables or Mollier diagrams to determine specific properties of the steam at the given pressures and temperatures, such as specific volume. The work done can be calculated using the formula: \[ W = P \times (V_2 - V_1) \] Where: - \( W \) is the work done - \( P \) is the constant pressure - \( V_1 \) and \( V_2 \) are the initial and final specific volumes In this particular problem, after performing the necessary calculations and consulting appropriate tables, the work done by the steam is determined to be 214 kJ.
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