4-7 Practice (continued) 6. Given: AAFD and ABGE are equilateral triangles. ZA ZB, DE = FG Prove: AD BE Statements 1) AAFD and ABGE are equilateral ▲ . 2) ZAZD ZAFD 3) ZB = /G ≈ ZBEG 4) ZA= ZB 5) ZA=D=B=/G 6) EF EF 7) DE FG 8) DE + EF = EF + FG 9) ? 10) ? 11) AD = BE Reasons 1) Given 2) ? 3) ? 4) Given 5) ? 6) ? 7) Given 8) ? 9) Segment Add. Post. 10) AAS 11) ? A E C. F Form K B G

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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complete the proof

 

4-7
Practice (continued)
6. Given: AAFD and ABGE are equilateral triangles.
ZA ≈ ZB, DE ≈ FG
Prove: AD≈ BE
Statements
1) AAFD and ABGE are equilateral A.
2) ZA ZD= ZAFD
3) ZB ≈ ZG ≈ZBEG
4) ZA ZB
5) ZA ≈ ZD ≈ ZB ≈ /G
6) EF = EF
7) DE= FG
8) DE + EF = EF + FG
9) ?
10) ?
11) AD = BE
Reasons
1) Given
2) ?
3) _?
4) Given
5) ?
6) ?
7) Given
D
8) ?
9) Segment Add. Post.
10) AAS
11) ?
A
E F
Form K
G
Transcribed Image Text:4-7 Practice (continued) 6. Given: AAFD and ABGE are equilateral triangles. ZA ≈ ZB, DE ≈ FG Prove: AD≈ BE Statements 1) AAFD and ABGE are equilateral A. 2) ZA ZD= ZAFD 3) ZB ≈ ZG ≈ZBEG 4) ZA ZB 5) ZA ≈ ZD ≈ ZB ≈ /G 6) EF = EF 7) DE= FG 8) DE + EF = EF + FG 9) ? 10) ? 11) AD = BE Reasons 1) Given 2) ? 3) _? 4) Given 5) ? 6) ? 7) Given D 8) ? 9) Segment Add. Post. 10) AAS 11) ? A E F Form K G
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