Please help me solve with work shown **Problem Statement:**Solve the inequality:\[\frac{-4}{x - 3} \leq \frac{7}{x + 5}\]Express your answer in interval notation.---**Solution:**1. **Rewrite the inequality:**\[\frac{-4}{x - 3} \leq \frac{7}{x + 5}\]2. **Find the critical points where the fractions are undefined:** - \( x - 3 = 0 \implies x = 3 \) - \( x + 5 = 0 \implies x = -5 \)3. **Rewrite the inequality to a common denominator:** This means making the denominators the same to combine the fractions. \[ \frac{-4(x + 5)}{(x - 3)(x + 5)} \leq \frac{7(x - 3)}{(x - 3)(x + 5)} \] Simplifying: \[ \frac{-4x - 20}{(x - 3)(x + 5)} \leq \frac{7x - 21}{(x - 3)(x + 5)} \]4. **Combine the fractions:** \[ \frac{-4x - 20 - (7x - 21)}{(x - 3)(x + 5)} \leq 0 \] Simplifying the numerator: \[ \frac{-4x - 20 - 7x + 21}{(x - 3)(x + 5)} \leq 0 \] \[ \frac{-11x + 1}{(x - 3)(x + 5)} \leq 0 \]5. **Find the critical points by setting numerator and denominator to zero:** Critical points are \( x = 3 \), \( x = -5 \), and \( -11x + 1 = 0 \) Solving \( -11x + 1 = 0 \) gives: \[ -11x + 1 = 0 \] \[ x = \frac{1}{11} \]6. **

Name: Please help me solve with work shown **Problem Statement:**Solve the i
Uploaded: 2024-03-20T07:07:37.000Z
Channel: Bartleby
Description: Please help me solve with work shown **Problem Statement:**Solve the inequality:\[\frac{-4}{x - 3} \leq \frac{7}{x + 5}\]Express your answer in interval notation.---**Solution:**1. **Rewrite the inequality:**\[\frac{-4}{x - 3} \leq \frac{7}{x + 5}\]2