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4 = 4 A Rq = 6 N ½ = 3A 3 = 1A R2 = 4 N 4 = 2 A R3 = 6N I5 = 3 A V2 RA 16 = 1A R5 = 4N Solve for V1, V2, and the power dissipated in R4

4 = 4 A Rq = 6 N ½ = 3A 3 = 1A R2 = 4 N 4 = 2 A R3 = 6N I5 = 3 A V2 RA 16 = 1A R5 = 4N Solve for V1, V2, and the power dissipated in R4

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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4 = 4 A R = 6 N V1 2 = 3 A 13 = 1 A R2 = 4 N R3 = 6N 4= 2 A 5 = 3 A ЗА V2 RA 16 = 1A R5 = 4 N Solve for V1, V2, and the power dissipated in R4
Transcribed Image Text:4 = 4 A R = 6 N V1 2 = 3 A 13 = 1 A R2 = 4 N R3 = 6N 4= 2 A 5 = 3 A ЗА V2 RA 16 = 1A R5 = 4 N Solve for V1, V2, and the power dissipated in R4
Expert Solution
Step 1

By kirchoff loop law in upper loop 

V1 - (4×6) - (1×6) - (3×4) = 0 

V1 = 42 volt 

By kirchoff loop law in lower right loop 

V2 + (1×6) - (3×4) = 0 

V1 = 6 volt 

By kirchoff loop law in lower left loop 

V2  - (3×4) + (1×R4) = 0 

R4 = 12-6 = 6 Ohm

 

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