4) 35.0 ml of 0.50M HA (K, 7.0 x 105) is titration with 0.25M NaOH. Calculate the pH at the endpoint. %3D

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### Titration Problem

**Problem Statement:**

4) 35.0 ml of 0.50M HA (\(K_a = 7.0 \times 10^{-5}\)) is titrated with 0.25M NaOH. Calculate the pH at the endpoint.

**Explanation:**

- HA is a generic weak acid with a given acid dissociation constant (\(K_a\)).
- The titration involves neutralizing this acid with a sodium hydroxide (\(NaOH\)) solution.
- The endpoint of a titration is where the amount of titrant added is stoichiometrically equivalent to the amount of substance initially in solution.
- The task is to calculate the pH at this point.

**Note:**

No graphs or diagrams accompany this problem.
Transcribed Image Text:### Titration Problem **Problem Statement:** 4) 35.0 ml of 0.50M HA (\(K_a = 7.0 \times 10^{-5}\)) is titrated with 0.25M NaOH. Calculate the pH at the endpoint. **Explanation:** - HA is a generic weak acid with a given acid dissociation constant (\(K_a\)). - The titration involves neutralizing this acid with a sodium hydroxide (\(NaOH\)) solution. - The endpoint of a titration is where the amount of titrant added is stoichiometrically equivalent to the amount of substance initially in solution. - The task is to calculate the pH at this point. **Note:** No graphs or diagrams accompany this problem.
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