4) 3/4 of the way up the pressure axis draw in a 1 atm pressure mark 5) From the 1 atm pressure mark, move straight right until you encounter your solid/liquid equilibrium Put a point for the normal melting point. Drop a line straight down to the temperature axis from this and write in the temperature 6) Continue straight right until you encounter your liquid/gas equilibrium line. Put a point there for the normal boiling point (you determined this in your experiment) 7) Drop a line straight down from your normal boiling point to the temperature access and write in the boiling point. Your diagram is sketched, please note it will not be to scale, but that is OK... we are just sketching the general shape. Thermodynamic data to use for your calculations: S.H.C. A C gas J/g*C C solid AH fusion Cliquid AH vapor Triple Point Melting Point J/g*C J/mol J/g*C J/mol n-hexane 13 kJ/mol 197.66 J/(mol K) 28.85 kJ/mol 142.6 J/(mol K) 178.0 K (-95.1 °C), 1.23 Pa -94 °C cyclohexane 2.68 kJ/mol 156 J/(mol K) 32 kJ/mol 105.3 J/(mol K) 279.48 K (6.33 °C), 5.388 kPa 6.47°C 2.68 J/(gK) 44.0 kJ/mol 1.54 J/(gK) 184.9 K (-88.2 °C), ? Pa -89 °C 2-propanol ethyl acetate 5.28 kJ/mol 10.48 kJ/mol 170 J/(mol K) 31.94 kJ/mol 125.8 J/(mol K) 189.3 K (-83.9 °C), ? Pa -83.6 °C Calculation space: Hexane balingint Clas aug): 677°C Energy required to heat from 25 C to boiling for 100.00 g of your liquid: 67.7°C-08°C= 42.7°C= 40.7K 9to md:100ghexaneX Imd hexane 1.16038. mahexane %3D 142.6 mdrk 名t198 706 5.S77,.. 16039 TEXAS INSTR SCUENG 2nd DRG 10% LOG PRB LN Ablc LIVD CIN-1 SIN 7. CIRVAD MEMVAR 4. Fく NO Calculation space: Energy required to heat from 25 C to boiling for 100.00 g of your liquid: Hexane baling paint (ela 67.7°C-08°0= 42.7°C= 40.7K 9 to md: 100ghe yaneX Imd hexane 1-16038. ma hexane 86.1789 140:6.mauk.16038.. (40.7K) =706 5.57...J lo00J 38.85k5/m)(.16038..nsl) = 33496963 RTXRJ-33476.963 J %31 7065.597J+ 33476.963J = 40340.34 40s43.J Energy required to heat from 25 C to boiling for 100.00 g water: 100-25°0 = 7S°C = 75K S. H.Cf gto mol: l0og waterx Imal water 18.015g = 3.550929. mal wat er t: 31500J