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4- 2 -6 -5. -4 -3 -2 -7 2 3 4 5 -2 -3 -4 -7 ++8+ Write an equation for the graph above. f(x) = to 3.

4- 2 -6 -5. -4 -3 -2 -7 2 3 4 5 -2 -3 -4 -7 ++8+ Write an equation for the graph above. f(x) = to 3.

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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The image shows a coordinate plane graph with a parabola. ### Graph Details: - **Axes:** The graph is drawn with both the x-axis and y-axis visible, each marked with unit intervals. - **X-axis Range:** -6 to 6 - **Y-axis Range:** -8 to 8 - **Parabola:** The graph depicts a downward-opening parabola with its vertex at the origin (0,0) and symmetrical along the y-axis. ### Problem Statement: "Write an equation for the graph above." ### Equation Box: The image includes a placeholder for the equation: \[ f(x) = \] To identify the specific equation of the parabola, observe the graph's structure and symmetry. Since the vertex is at the origin and it's a downward-opening parabola (suggesting a negative coefficient for \( x^2 \)), this can be represented in general form as: \[ f(x) = -ax^2 \] An accurate equation will be established by evaluating the scale and using specific points for calculation.
Transcribed Image Text:The image shows a coordinate plane graph with a parabola. ### Graph Details: - **Axes:** The graph is drawn with both the x-axis and y-axis visible, each marked with unit intervals. - **X-axis Range:** -6 to 6 - **Y-axis Range:** -8 to 8 - **Parabola:** The graph depicts a downward-opening parabola with its vertex at the origin (0,0) and symmetrical along the y-axis. ### Problem Statement: "Write an equation for the graph above." ### Equation Box: The image includes a placeholder for the equation: \[ f(x) = \] To identify the specific equation of the parabola, observe the graph's structure and symmetry. Since the vertex is at the origin and it's a downward-opening parabola (suggesting a negative coefficient for \( x^2 \)), this can be represented in general form as: \[ f(x) = -ax^2 \] An accurate equation will be established by evaluating the scale and using specific points for calculation.
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