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4 12d2= -dx = x² - 1 (A) B D 4 ln x² - 1| + C 2 ln+C 4sin ¹x + C 4tan ¹x + C

4 12d2= -dx = x² - 1 (A) B D 4 ln x² - 1| + C 2 ln+C 4sin ¹x + C 4tan ¹x + C

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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The problem involves evaluating the integral of the function: \[ \int \frac{4}{x^2 - 1} \, dx \] The multiple choice options for the integral are: A) \( 4 \ln |x^2 - 1| + C \) B) \( 2 \ln \left| \frac{x-1}{x+1} \right| + C \) C) \( 4 \sin^{-1} x + C \) D) \( 4 \tan^{-1} x + C \) Where \( C \) represents the constant of integration.
Transcribed Image Text:The problem involves evaluating the integral of the function: \[ \int \frac{4}{x^2 - 1} \, dx \] The multiple choice options for the integral are: A) \( 4 \ln |x^2 - 1| + C \) B) \( 2 \ln \left| \frac{x-1}{x+1} \right| + C \) C) \( 4 \sin^{-1} x + C \) D) \( 4 \tan^{-1} x + C \) Where \( C \) represents the constant of integration.
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