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4-10 GAUSS-SEIDEL ITERATION Do 5 steps, starting from x0 = 1 1 1 and using 6S in the computation. int. Make sure that you solve each equation for the variable that has the largest coefficient (why). Show the details. 4. 4x1 - X2 = 21 -x1 + 4x2 - X3=-45 - x2 + 4x3 = 33 5. 10x1 + X2 + X3 = 6 x1 + 10x2 + X3 = 6 x1 + X2 + 10x3 = 6 6. x2 + 7x3 = 25.5 5x1 + x2 = 0 x16x2 x3 = -10.5 7. 5x1 - 2x2 = 18 -2x1 +10x2 - 2x3 = -60 - 2x215x3128 8. 3x1 + 2x2 x3 = 7 x13x22x3 = 4 2x1 + x2+3x3 = 7 9. 5x1 + x2 + 2x3 = 19 x14x22x3 = -2 2x13x2+8x3 = 39 10. 4x1 + 5x3 == 12.5 X1+6x2 + 2x3 = 18.5 8x12x2 x3 = -11.5

4-10 GAUSS-SEIDEL ITERATION Do 5 steps, starting from x0 = 1 1 1 and using 6S in the computation. int. Make sure that you solve each equation for the variable that has the largest coefficient (why). Show the details. 4. 4x1 - X2 = 21 -x1 + 4x2 - X3=-45 - x2 + 4x3 = 33 5. 10x1 + X2 + X3 = 6 x1 + 10x2 + X3 = 6 x1 + X2 + 10x3 = 6 6. x2 + 7x3 = 25.5 5x1 + x2 = 0 x16x2 x3 = -10.5 7. 5x1 - 2x2 = 18 -2x1 +10x2 - 2x3 = -60 - 2x215x3128 8. 3x1 + 2x2 x3 = 7 x13x22x3 = 4 2x1 + x2+3x3 = 7 9. 5x1 + x2 + 2x3 = 19 x14x22x3 = -2 2x13x2+8x3 = 39 10. 4x1 + 5x3 == 12.5 X1+6x2 + 2x3 = 18.5 8x12x2 x3 = -11.5

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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4-10 GAUSS-SEIDEL ITERATION Do 5 steps, starting from x0 = 1 1 1 and using 6S in the computation. int. Make sure that you solve each equation for the variable that has the largest coefficient (why). Show the details. 4. 4x1 - X2 = 21 -x1 + 4x2 - X3=-45 - x2 + 4x3 = 33 5. 10x1 + X2 + X3 = 6 x1 + 10x2 + X3 = 6 x1 + X2 + 10x3 = 6 6. x2 + 7x3 = 25.5 5x1 + x2 = 0 x16x2 x3 = -10.5 7. 5x1 - 2x2 = 18 -2x1 +10x2 - 2x3 = -60 - 2x215x3128 8. 3x1 + 2x2 x3 = 7 x13x22x3 = 4 2x1 + x2+3x3 = 7 9. 5x1 + x2 + 2x3 = 19 x14x22x3 = -2 2x13x2+8x3 = 39 10. 4x1 + 5x3 == 12.5 X1+6x2 + 2x3 = 18.5 8x12x2 x3 = -11.5
Transcribed Image Text:4-10 GAUSS-SEIDEL ITERATION Do 5 steps, starting from x0 = 1 1 1 and using 6S in the computation. int. Make sure that you solve each equation for the variable that has the largest coefficient (why). Show the details. 4. 4x1 - X2 = 21 -x1 + 4x2 - X3=-45 - x2 + 4x3 = 33 5. 10x1 + X2 + X3 = 6 x1 + 10x2 + X3 = 6 x1 + X2 + 10x3 = 6 6. x2 + 7x3 = 25.5 5x1 + x2 = 0 x16x2 x3 = -10.5 7. 5x1 - 2x2 = 18 -2x1 +10x2 - 2x3 = -60 - 2x215x3128 8. 3x1 + 2x2 x3 = 7 x13x22x3 = 4 2x1 + x2+3x3 = 7 9. 5x1 + x2 + 2x3 = 19 x14x22x3 = -2 2x13x2+8x3 = 39 10. 4x1 + 5x3 == 12.5 X1+6x2 + 2x3 = 18.5 8x12x2 x3 = -11.5
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