[3yx? - 1] dx + [x3 + 6y – y2] dy = 0 And that "F" is F = yx³ - x + 8 (y) Find the equation that represents g(y). A8(y) = 6y - y2 + C 1 8 (y) = 2yx³ + 3y2 - y³ + C 8 (y) = 6y2 - y3 + C D 3y? - + c 8 (y) = -x* + (E) 8(y) = = 3y2 . C P(y) = C +

Q: S ds J V3s? + 1

A: To evaluate the given integral

Q: 64y2+7=32

A: 64y2+7=32

Q: 4y-12=0

A: 4y = 12 y = 3

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A:

Q: 4w=25

A: topic - linear equation

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A:

Q: -3w+5=23

A:

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A: Here we take a general matrix of the given set then find the basis.

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A: Given  -4d=-64

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A: -1+n=15

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A:

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A:

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A:

Q: -8 = 6+n

A:

Q: 2: Find: L-1[: 1 3 - 3]

A:

Q: 6+12=

A: Given,          6+12

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A:

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A: Given,   A+12=13     We will solve it for the value of A

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A: Given,          6+197

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A:

Q: dx 4е2я — 8ет + 5

A: This question can be solved using the concept of special integrals.

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A: Let the given integral be y - y = ∫z1-z2 dz           ..............(1)Let,z = sinx…

Q: I need help with 6b

A: