3y - t2 dy = 0; y(1) = 1 + y5 dt' 2y4 O t? = y°(3- 2y2) O t3 = y(4- 3y?) O t? = y(7-6y?) O t2 = y²(6 – 5y²)
3y - t2 dy = 0; y(1) = 1 + y5 dt' 2y4 O t? = y°(3- 2y2) O t3 = y(4- 3y?) O t? = y(7-6y?) O t2 = y²(6 – 5y²)
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
Solve this initial value problem.
Transcribed Image Text:3y? - t2 dy
t
+
dt
3D 0; у(1) — 1
2yA
O t2= y(3-2y?)
O t3 = y(4-3y3)
O t3 = y(7 – 6y?)
O t? = y?(6 - 5y?)
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