3x5 ·S= 3x4+6x³-3x² - 6x x²-2x-In -1 [ + €². (x-1) 1/6(x+2) 16/3 (x+1) 1/2 +C x² - 4x (x − 1) 1/6(x+2) 16/3- (x+1)1/2 +C 2 [(x 11/8( 1) 1/6(x7) 16/3 1 Evaluate (A) (B) Y + In -dx. using method of partial fractions.
3x5 ·S= 3x4+6x³-3x² - 6x x²-2x-In -1 [ + €². (x-1) 1/6(x+2) 16/3 (x+1) 1/2 +C x² - 4x (x − 1) 1/6(x+2) 16/3- (x+1)1/2 +C 2 [(x 11/8( 1) 1/6(x7) 16/3 1 Evaluate (A) (B) Y + In -dx. using method of partial fractions.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Evaluate using partial fractions
![Evaluate
·S=
(A) x²-2x-In
x² - 4x
(B)
2
x² - 4x
(C)
2
x²-2x
D
2
3x5
3x4+6x³-3x² - 6x
+ In
+ In
+ In
-dx. using method of partial fractions.
+C
+C
T
²]+c
+C
+C
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
(x-1) 1/6(x+2) 16/3
x + 1
(x-1) 1/6(x+2) 16/3
(x+1) 1/2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbad1ddda-f243-4b07-aa2a-b3241140a891%2F1bd86c20-53de-4ede-bd7f-1fa1a3af719c%2Fz72xo6k_processed.png&w=3840&q=75)
Transcribed Image Text:Evaluate
·S=
(A) x²-2x-In
x² - 4x
(B)
2
x² - 4x
(C)
2
x²-2x
D
2
3x5
3x4+6x³-3x² - 6x
+ In
+ In
+ In
-dx. using method of partial fractions.
+C
+C
T
²]+c
+C
+C
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
(x-1) 1/6(x+2) 16/3
x + 1
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
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