3x5 Evaluate S 3x4+6x33x2 - 6x O x2−2x +In 2 x²-2x-In O x² - 4x 2 O x² - 4x 2 -dx, using method of partial fractions. +C 1/² ] + C ²- ] + C 1/² ] + C 2) 16/3 ] + C (x-1) 1/6(x+2) 16/3 (x+1) 1/2 (x− 1) 1/6(x+2) 16/3 (x+1) 1/2 (x− 1) 1/6(x+2) 16/3 - (x+1) 1/2 ¯ (x − 1) 1/6(x+2) 16/ x+1 + In +41 +In
3x5 Evaluate S 3x4+6x33x2 - 6x O x2−2x +In 2 x²-2x-In O x² - 4x 2 O x² - 4x 2 -dx, using method of partial fractions. +C 1/² ] + C ²- ] + C 1/² ] + C 2) 16/3 ] + C (x-1) 1/6(x+2) 16/3 (x+1) 1/2 (x− 1) 1/6(x+2) 16/3 (x+1) 1/2 (x− 1) 1/6(x+2) 16/3 - (x+1) 1/2 ¯ (x − 1) 1/6(x+2) 16/ x+1 + In +41 +In
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![3x5
Evaluate
S
3x4+6x33x2 - 6x
O x2−2x
+In
2
x²-2x-In
-dx, using method of partial fractions.
1/² ] + C
+C
²- ] + C
1/² ] + C
2) 16/3 ] + C
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
(x− 1) 1/6(x+2) 16/3
(x+1) 1/2
(x− 1) 1/6(x+2) 16/3 -
(x+1) 1/2
+ In
+41
(x− 1) 1/6(x+2) 16/
+In
x+1
O x² - 4x
2
O x² - 4x
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa062ac3d-563d-4e9a-82ab-6e677b881d0b%2F91047956-a973-4926-b586-4c4586c7a6cf%2Fvo16bdv_processed.png&w=3840&q=75)
Transcribed Image Text:3x5
Evaluate
S
3x4+6x33x2 - 6x
O x2−2x
+In
2
x²-2x-In
-dx, using method of partial fractions.
1/² ] + C
+C
²- ] + C
1/² ] + C
2) 16/3 ] + C
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
(x− 1) 1/6(x+2) 16/3
(x+1) 1/2
(x− 1) 1/6(x+2) 16/3 -
(x+1) 1/2
+ In
+41
(x− 1) 1/6(x+2) 16/
+In
x+1
O x² - 4x
2
O x² - 4x
2
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