3x5 3x4+6x33x2 - 6x + In Evaluate S Ox²–2x (x-1) 1/6(x+2) 16/3 (x+1) 1/2 2 Ox²-4x (x-1) 1/6(x+2) 16/3 (x+1) ¹/2 2 Ox²-4x (x-1) 1/6(x+2) 16. 16/3 + In +C 2 x+1 2x 1 + C (x-1) 1/6(x+2) 16/3 (x+1) 1/2 x2-2x-In [(x +C + In dx using method of partial fractions. +C +C
3x5 3x4+6x33x2 - 6x + In Evaluate S Ox²–2x (x-1) 1/6(x+2) 16/3 (x+1) 1/2 2 Ox²-4x (x-1) 1/6(x+2) 16/3 (x+1) ¹/2 2 Ox²-4x (x-1) 1/6(x+2) 16. 16/3 + In +C 2 x+1 2x 1 + C (x-1) 1/6(x+2) 16/3 (x+1) 1/2 x2-2x-In [(x +C + In dx using method of partial fractions. +C +C
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.5: The Binomial Theorem
Problem 16E
Related questions
Question
![3x5
Evaluate
S
3x4+6x33x² - 6x
O r2_2r
(x-1) 1/6(x+2) 16/3
*² = 2² + C
+ In
+C
2
(x+1) 1/2
O x² - 4x
+ In
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
+C
2
Ox² - 4x
(x-1) 1/6(x+2) 16/3
2 + + C
In
+C
x+1
x2-2x-In
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
²1+0
+C
dx, using method of partial fractions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe468eb5d-0923-42a5-8ff0-ffc1dff1641e%2F79562bac-be6c-4d69-9fbf-d1ccf24eafc0%2Ftrd93v_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3x5
Evaluate
S
3x4+6x33x² - 6x
O r2_2r
(x-1) 1/6(x+2) 16/3
*² = 2² + C
+ In
+C
2
(x+1) 1/2
O x² - 4x
+ In
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
+C
2
Ox² - 4x
(x-1) 1/6(x+2) 16/3
2 + + C
In
+C
x+1
x2-2x-In
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
²1+0
+C
dx, using method of partial fractions.
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