3x5 3x4+6x33x² - 6x Evaluate A B (C) (D) ·S= x²-2x-In x² - 4x 2 x² - 4x 2 x² - 2x 2 + In + In + In -dx, using method of partial +C 2²]+C ²] + C +C (x-1) 1/6(x+2) 16/3 (x+1) 1/2 (x-1) 1/6(x+2) 16 16/3 x + 1 (x-1) 1/6(x+2) 16/3 (x+1) 1/2 (x-1) 1/6(x+2) 16 16/3 (x+1) 1/2
3x5 3x4+6x33x² - 6x Evaluate A B (C) (D) ·S= x²-2x-In x² - 4x 2 x² - 4x 2 x² - 2x 2 + In + In + In -dx, using method of partial +C 2²]+C ²] + C +C (x-1) 1/6(x+2) 16/3 (x+1) 1/2 (x-1) 1/6(x+2) 16 16/3 x + 1 (x-1) 1/6(x+2) 16/3 (x+1) 1/2 (x-1) 1/6(x+2) 16 16/3 (x+1) 1/2
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
Related questions
Question
![3x5
3x4+6x33x² - 6x
Evaluate
A
B
(C)
(D
·S=
x²-2x-In
x² - 4x
2
x² - 4x
2
x² - 2x
2
+ In
+ In
+ In
-dx, using method of partial fractions.
+C
2²]+C
+C
+C
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
(x-1) 1/6(x+2) 16
16/3
x + 1
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
(x-1) 1/6(x+2) 16
16/3
(x+1) 1/2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F14c95898-5ecc-4921-a01a-ef8f45c5be7f%2F9327f98f-6f63-4ee3-8fec-b670266a25ce%2Fm63iq38_processed.png&w=3840&q=75)
Transcribed Image Text:3x5
3x4+6x33x² - 6x
Evaluate
A
B
(C)
(D
·S=
x²-2x-In
x² - 4x
2
x² - 4x
2
x² - 2x
2
+ In
+ In
+ In
-dx, using method of partial fractions.
+C
2²]+C
+C
+C
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
(x-1) 1/6(x+2) 16
16/3
x + 1
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
(x-1) 1/6(x+2) 16
16/3
(x+1) 1/2
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