3x5 3x4+6x3-3x2 - 6x (x-1) 1/6(x+2) 16/3- +In x + 1 ¯ (x− 1) 1/6(x+2) 16/3- (x+1) 1/2 ¯ (x− 1) 1/6(x+2) 16/3- (x+1) 1/2 (x-1) 1/6(x+2) 16/3 (x+1) 1/2 aluate ·S= x² - 4x 2 =x²-2x +In 2 x²-2x-In x² - 4x 2 + In -dx using method of partial fractions. 2²- ] + C +C 2) 1073 ] + ²]+c 161²] + C 2) 10/²3 ] + ²7+ C +C
3x5 3x4+6x3-3x2 - 6x (x-1) 1/6(x+2) 16/3- +In x + 1 ¯ (x− 1) 1/6(x+2) 16/3- (x+1) 1/2 ¯ (x− 1) 1/6(x+2) 16/3- (x+1) 1/2 (x-1) 1/6(x+2) 16/3 (x+1) 1/2 aluate ·S= x² - 4x 2 =x²-2x +In 2 x²-2x-In x² - 4x 2 + In -dx using method of partial fractions. 2²- ] + C +C 2) 1073 ] + ²]+c 161²] + C 2) 10/²3 ] + ²7+ C +C
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.4: Complex And Rational Zeros Of Polynomials
Problem 15E
Related questions
Question
![3x5
3x4+6x33x2 - 6x
x² - 4x
+ In
2
O x2−2x
+ In
2
x²-2x-In
x² - 4x
2
·S=
Evaluate
+ In
-dx using method of partial fractions.
=]+C
с
+C
(x-1) 1/6(x+2) 16/3
x + 1
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
(x-1) 1/6(x+2) 16/3-
(x+1) 1/2
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
+C
| 10/²] + C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbb6b4b0a-4413-401b-81f4-9d7dc82bdabe%2Fca504d32-bbc6-49d2-8764-92f381d8670a%2Fowfnwin_processed.png&w=3840&q=75)
Transcribed Image Text:3x5
3x4+6x33x2 - 6x
x² - 4x
+ In
2
O x2−2x
+ In
2
x²-2x-In
x² - 4x
2
·S=
Evaluate
+ In
-dx using method of partial fractions.
=]+C
с
+C
(x-1) 1/6(x+2) 16/3
x + 1
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
(x-1) 1/6(x+2) 16/3-
(x+1) 1/2
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
+C
| 10/²] + C
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