3x5 3x4+6x3-3x2 - 6x uate -dx, using method of partial fractions. x²-2x O [ (x − 1) 1/6(x+2) 16/3 - +In +2) 16/3] + 0 2 (x+1) 1/2 3 [ + 1 2-2x-In (x-1) 1/6(x+2) 16/3 (x+1) 1/2 4+/21) C +C =) x² = 4x + 10 [ + C +In (x-1) 1/6(x+2) 16/3- (x+1) 1/2 +12) 16/3] +C 2 - x² = 4x + - [(x-1) 1/6(x+2) 16/3- +In 10(x + 2) 16/3 ] + 0 2 x + 1
3x5 3x4+6x3-3x2 - 6x uate -dx, using method of partial fractions. x²-2x O [ (x − 1) 1/6(x+2) 16/3 - +In +2) 16/3] + 0 2 (x+1) 1/2 3 [ + 1 2-2x-In (x-1) 1/6(x+2) 16/3 (x+1) 1/2 4+/21) C +C =) x² = 4x + 10 [ + C +In (x-1) 1/6(x+2) 16/3- (x+1) 1/2 +12) 16/3] +C 2 - x² = 4x + - [(x-1) 1/6(x+2) 16/3- +In 10(x + 2) 16/3 ] + 0 2 x + 1
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
12
![3x5
3x4+6x3-3x2 - 6x
[(x-1)
(x-1) 1/6(x+2) 16/3-
(x+1) 1/2
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
(x-1) 1/6(x+2) 16/3
x + 1
Evaluate
·S
℗ x² - 2x + 10√
A
2
℗
B
x2-2x-In
C
D
x2-4x² + 20 -
+In
2
x² - 4x
2
1 [ (x-1)
+ In
dx, using method of partial fractions.
²1+ C
+C
1613]+
+C
+C
21+
+C](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F10357822-1520-45c6-8e52-af6da26173a3%2Fb76325cf-0854-4954-b41c-cf8995a972bd%2F8ym7w3_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3x5
3x4+6x3-3x2 - 6x
[(x-1)
(x-1) 1/6(x+2) 16/3-
(x+1) 1/2
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
(x-1) 1/6(x+2) 16/3
x + 1
Evaluate
·S
℗ x² - 2x + 10√
A
2
℗
B
x2-2x-In
C
D
x2-4x² + 20 -
+In
2
x² - 4x
2
1 [ (x-1)
+ In
dx, using method of partial fractions.
²1+ C
+C
1613]+
+C
+C
21+
+C
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