3x1 - 2x2+ X3 =-10 2х, + 6х, — 4x, %3 44 — X, — 2х, + 5х; —-26

Q: xp 4x (1)(-2e

A: here we will use exponential theorem for solving and after that apply integration p[roperty.

Q: -9=x-4

A: -9 + 9 = x - 4 + 9

Q: b. If 8x − 0 = 3x + 5 , then x=

A: Consider the provided equation,

Q: 3x+8y+13x=

A: Answer

Q: 15

A:

Q: 1x1=?

A: apply multiplication

Q: 7x - 2y = 19  3x + 5y = 14

A:

Q: - 1/2x - 3 = - 9

A: SOLUTION-

Q: 3x-(4+5x)=12

A: We will find the value of x.

Q: 3x + 5x + 6 + 10 =

A: To solve these type of question follow these steps : Add same variables together and then equate.

Q: Solve the equation -7x-17 = -38 for x. • Write your answer as a number only. • Round your answer to…

A:

Q: (-8, -5);m=-3/4

A:

Q: 3x + 4y = 19 3x + 6y = 33

A:

Q: -9 + 5x + 6 = -5(x +1) + 2

A:

Q: 2x+5y=-4 -2x+3y=20

A: The given equations are 2x + 5y = –4 and –2x + 3y = 20. Add the given equations as follows. Thus,…

Q: 2x-2y=-8 x-2y=-9

A:

Q: x=-2 x+3y=4

A: Given: x=-2 and x+3y=4 To find the value of y, we need to substitute x=-2  in x+3y=4.

Q: 3x + 5 = -5x + 3 ×=

A:

Q: Evaluate x2 - 6x + 3, for x = 7

A: We have to evaluate x2-6x+3 for x=7. Let Px=x2-6x+3 Now, at x=7 P7=72-6·7+3=49-42+3=52-42=10

Q: 3x³ +x² -4 3x+x2. dx x+2x

A:

Q: 2x-4y=-22 2x-3y=-19

A:

Q: x2+16x=?

A: factorization of quadratic

Q: २e १x- 2 e/~3 5ex

A:

Q: 4+2x

A:

Q: - 14 = X + 12

A: given that    -14 = X + 12

Q: 3x-2-2x-9=20

A: Given the equation, 3x-2-2x-9=20

Q: -3x+8=2

A: Given that  -3x+8=2 We need to find value of x

Q: |2xe"dx + C

A: Consider the integral  ∫2xe4xdx

Q: Find the value of X

A: To find: The value of x. Calculation: The line drawn from centre to the point of contact of tangent…

Q: -8x + 12x + 3x= -77

A: given  -8x+12x+3x=-77

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.