3x – 4 Find the asymptotes (if any) and express them as linear equations: g(x) = x+2

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
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Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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please make sure give the intercepts of the equation.

**Finding Asymptotes of Rational Functions**

In this exercise, we analyze the function \( g(x) = \frac{3x - 4}{x + 2} \) to find its asymptotes and express them as linear equations.

1. **Vertical Asymptote**:
   - Vertical asymptotes occur where the denominator is zero (and the numerator is non-zero). 
   - Set the denominator equal to zero: 
     \[
     x + 2 = 0 
     \]
   - Solving for \( x \), we find \( x = -2 \).
   - Thus, there is a vertical asymptote at \( x = -2 \).

2. **Horizontal Asymptote**:
   - Horizontal asymptotes are determined by comparing the degrees of the numerator and the denominator.
   - The degrees of both the numerator \( (3x - 4) \) and the denominator \( (x + 2) \) are 1.
   - When the degrees are equal, the horizontal asymptote is given by the ratio of the leading coefficients.
   - The leading coefficient of the numerator is 3, and for the denominator, it is 1.
   - Hence, the horizontal asymptote is:
     \[
     y = \frac{3}{1} = 3
     \]

Therefore, the function \( g(x) = \frac{3x - 4}{x + 2} \) has a vertical asymptote at \( x = -2 \) and a horizontal asymptote at \( y = 3 \).
Transcribed Image Text:**Finding Asymptotes of Rational Functions** In this exercise, we analyze the function \( g(x) = \frac{3x - 4}{x + 2} \) to find its asymptotes and express them as linear equations. 1. **Vertical Asymptote**: - Vertical asymptotes occur where the denominator is zero (and the numerator is non-zero). - Set the denominator equal to zero: \[ x + 2 = 0 \] - Solving for \( x \), we find \( x = -2 \). - Thus, there is a vertical asymptote at \( x = -2 \). 2. **Horizontal Asymptote**: - Horizontal asymptotes are determined by comparing the degrees of the numerator and the denominator. - The degrees of both the numerator \( (3x - 4) \) and the denominator \( (x + 2) \) are 1. - When the degrees are equal, the horizontal asymptote is given by the ratio of the leading coefficients. - The leading coefficient of the numerator is 3, and for the denominator, it is 1. - Hence, the horizontal asymptote is: \[ y = \frac{3}{1} = 3 \] Therefore, the function \( g(x) = \frac{3x - 4}{x + 2} \) has a vertical asymptote at \( x = -2 \) and a horizontal asymptote at \( y = 3 \).
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