3)The following molarities were calculated from replicate standardizations of a NaOH solution: 0.502 8, 0.502 9, 0.502 3, 0.503 1, 0.502 6, 0.5027, 0.503 4, and 0.502 5. Assuming no systematic errors, within what range are you 90% certain that the true mean value of the molarity falls? Sample size(n) Mean Standard Deviation Degree of fredom Confidence interval Student's t 90% Confidence Interval Concentrations 0.5028 0.5029 0.5023 0.5031 0.5026 0.5027 0.5034 0.5025 8 0.5027875 0.00034821 7 0.9 -1.414923928 -0.000174192 |n-1-8-1-7
3)The following molarities were calculated from replicate standardizations of a NaOH solution: 0.502 8, 0.502 9, 0.502 3, 0.503 1, 0.502 6, 0.5027, 0.503 4, and 0.502 5. Assuming no systematic errors, within what range are you 90% certain that the true mean value of the molarity falls? Sample size(n) Mean Standard Deviation Degree of fredom Confidence interval Student's t 90% Confidence Interval Concentrations 0.5028 0.5029 0.5023 0.5031 0.5026 0.5027 0.5034 0.5025 8 0.5027875 0.00034821 7 0.9 -1.414923928 -0.000174192 |n-1-8-1-7
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Please explains how to get studentt's t and 90% confidence interval with excel, because I got different answers using the formula, and doing with the regular formulas.

Transcribed Image Text:**Determining the 90% Confidence Interval for NaOH Solution Molality**
The following molarities were calculated from replicate standardizations of a NaOH solution, with no systematic errors assumed. The purpose is to determine the range within which we can be 90% certain that the true mean value of the molarity falls.
**Concentration Data:**
- 0.5028
- 0.5029
- 0.5023
- 0.5031
- 0.5026
- 0.5027
- 0.5034
- 0.5025
**Statistical Calculations:**
- **Sample Size (n):** 8
- **Mean Molarity:** 0.5027875
- **Standard Deviation:** 0.00034821
- **Degrees of Freedom:** 7 (calculated as n-1)
- **Confidence Level:** 90%
**Confidence Interval Calculations:**
Using the Student's t-distribution for a 90% confidence level:
- **Student's t value:** -1.414923928
- **90% Confidence Interval:** -0.000174192
In conclusion, the 90% confidence interval can be calculated around the mean molarity to identify the range within which the true mean is likely to lie. This interval, derived from the sample data and statistical calculations, is crucial for understanding the variability and reliability of the molarity measurements.
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