Determine the value of the plastic load Pn using the concept of collapse mechanism. For the properties of the steel section, use the given designated wide-flange beam section below. (Assume?? = 415 ???). Pn3Pn2m3m1m FlangeWebMassAreaWidthThicknessthicknessDepth(mm)(kg/m)(mm²)(mm)(mm)(mm)3144010078538433.519.7Axis X-XAxis Y-YS= Ilc(10³ mm³)r = IJA(mm)S = I|c(10' mm³)= VIJAr =(10 mm*)(10 mm4)(mm)4 29010 9003283151 64088.6

Answered: Image /qna-images/answer/78dae68c-5616-4c90-b534-d9caca079715.jpg

Answered: 3Pn Pn 1m Зт 2m

Engineering

Civil Engineering

3Pn Pn 1m Зт 2m

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

System of Forces

A force is an external influence or agent that changes the state of a system. According to Newton's second law, the force applied to a body is proportional to the change in momentum of a body. Hence, whenever a force is applied to a body, its momentum changes. If the body is at rest, under the action of force, its state of rest changes to motion. In other words, the magnitude of the momentum of the body changes from zero to a measurable value. Similarly, if the body possesses some initial velocity, it has some associated momentum, the effect of force can cause the body to halt or come to rest, that is, the momentum reduces to zero.

Question

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Determine the value of the plastic load Pn using the concept of collapse mechanism. For the properties of the steel section, use the given designated wide-flange beam section below. (Assume ?? = 415 ???).

Flange
Web
Mass
Area
Width
Thickness
thickness
Depth
(mm)
(kg/m)
(mm²)
(mm)
(mm)
(mm)
314
40100
785
384
33.5
19.7
Axis X-X
Axis Y-Y
S= Ilc
(10³ mm³)
r = IJA
(mm)
S = I|c
(10' mm³)
= VIJA
r =
(10 mm*)
(10 mm4)
(mm)
4 290
10 900
328
315
1 640
88.6

Branch of science that deals with the stationary and moving bodies under the influence of forces.

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