3n+1 n→∞⁰ 7n-3 lim, 3 7 1 lim→∞ ((−1)" + −) does not exist. n
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Use the definition of Convergent Sequences to prove
![The image contains two mathematical expressions related to limits as follows:
1. The first expression is:
\[
\lim_{n \to \infty} \frac{3n + 1}{7n - 3} = \frac{3}{7}.
\]
This represents the limit of the sequence \(\frac{3n + 1}{7n - 3}\) as \(n\) approaches infinity. The limit is \(\frac{3}{7}\).
2. The second expression is:
\[
\lim_{n \to \infty} \left((-1)^n + \frac{1}{n}\right) \text{ does not exist.}
\]
This indicates that the limit of the sequence \((-1)^n + \frac{1}{n}\) does not exist as \(n\) approaches infinity. The oscillating behavior of \((-1)^n\) leads to the non-existence of the limit.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe00cebfb-aec4-474d-8979-79a2d105b819%2Fc282bb70-dc5e-4d20-9b7d-84da60252f9f%2Flw1yln_processed.png&w=3840&q=75)
Transcribed Image Text:The image contains two mathematical expressions related to limits as follows:
1. The first expression is:
\[
\lim_{n \to \infty} \frac{3n + 1}{7n - 3} = \frac{3}{7}.
\]
This represents the limit of the sequence \(\frac{3n + 1}{7n - 3}\) as \(n\) approaches infinity. The limit is \(\frac{3}{7}\).
2. The second expression is:
\[
\lim_{n \to \infty} \left((-1)^n + \frac{1}{n}\right) \text{ does not exist.}
\]
This indicates that the limit of the sequence \((-1)^n + \frac{1}{n}\) does not exist as \(n\) approaches infinity. The oscillating behavior of \((-1)^n\) leads to the non-existence of the limit.
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