3n 2n n S " S"(sin x + cos y)e? dx dy dz 2n 'n A. 2n(e2n + e3™) в. 2п(е2т — езт) c. 2n(e3™ + e2") D. 2n(e3 – e2™) A В

Q: d dx صواب ihi

A: Given Jn(x) is bessel function and from derivative of bessel function we obtain required result.

Q: (5-)dx ー3 2人 がー。 Sin(x) d X

A: 3)   ∫-34(5-x2) dx=5x-x24-34                                =54+3-16-94…

Q: s+1) (a) L-1 4s2 +1 (b) L-1 s4 + s] (e) E{/ c{[e cos(r) dr.

A:

Q: sinhx dx 1+ coshx ) A 1+ coshx B (1+coshx)? (1+coshx)² D 1+ coshx

A: We have to find

Q: (x+1)dx x² + 2x – 8 24. - 8

A: To integrate: ∫(x+1)dxx2+2x-8 Solution: Given,…

Q: Evaluate fa tan() da 1 글 [(22 + 2a) tan-1 ()-피+C o b을[(22+ 2a) tan-1 () + z] +C 2a) tan-1 ()- 피 +C…

A: Solve the above integration.

Q: xsin ax 2 2 (x²-x²) 1/2 Show that [²= - dx - TV J₁ (ay) 2

A:

Q: Q3: Solve X dy dx +34 Sinx X

A:

Q: sin (3x+1)dx 4 cos (3x+1) C

A:

Q: Sohe nin(x+y) + cos(x+y) Solve = sin

A:

Q: d? -(sin-'(x²)) dx2 2– 4x4 A 3 2– 2x4 B 3 2+2x4 3. 2+4x4 D

A: Here we have to use the concept of derivative

Q: 4 sin(x) cos(z) + 2 sin(z) – 2cos(z) – 1 = 0

A:

Q: e3 sin(5x) dx %3D

A:

Q: -2m (sin x) dx

A:

Q: xe* dx J, (1+ x)²

A: ∫01 x ex(1+x)2 dx

Q: (х — 3)dx J («+2)(х + 1)?

A:

Q: Find the general Solution of the complement OF the following differential equation y"-7y) -6y=013…

A:

Q: Q: Solve y+8= Cos (x) ナ3sin(2x)

A: Given: y''+y=cos x+3 sin 2xCE: m2+1=0⇒m=±iCF: e(0)x( Acos x +B sin x)=Acos x +B sin x

Q: instead of cube there is a square in that equation 3(2x-1)2 please solve

A: Given,           ∫2x-1cos32x-12+632x-12+6dx

Q: (d) : 2x² – 8x – 13 dx x² – 5x – 6 2.

A: As per company rules we can answer only first question and rest can be reposted

Q: 3) S cos(Inx) dx

A: according to guidelines we should able to do only one question at a time #3

Q: sin(3x - 2) csc(4x + 3)' dM solve for dr

A: Here we can find the derivative as below with respect to x

Q: S retan³ (e)sec² (e²)dx

A:

Q: 5-2x dy if y = cos Find dx %3D 5+ 2x

A:

Q: х -14х + 5 3. x(х - 1)(х — 5) - dx

A:

Q: d²y + y = 4 cos x dx² Please solve this equation by hypothesis (V)

A:

Q: (e) S, In|x| dx.

A:

Q: 1 dx 2 21+2*2 ху

A:

Q: dx Evaluate V- x² – 4x – 1

A:

Q: c2 1 dx x² +1 4. e* + 0.

A:

Q: (1+e' )dx +e" (1-)dy = 0 y

A: To find the solution of the below differential equation.

Q: (xy cos.xy +sin xy)dx +(x² cos.xy +e' )dy=0.

A: We have to solve given problem:

Q: e-32 sec(e-32) tan(e-³²)dz

A:

Q: (4(x2-1) dx x²(x+2)

A: We will use partial fraction here