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3A2: Integrate their knowledge of 2, symmetry, and molecular formula (MF) with ¹3C NMR data and determine organic structure. Write a line-angle structure that is consistent with a MF of C7H10O and the ¹3C NMR data provided. You must label all the carbon atoms in your structure with the correct Roman letters (a, b, c, d, etc.) in the NMR data. ¹H Decoupled a b c 240 ppm d ef 0 240 DEPT 135° b c ppm 0 240 DEPT 90° b c ppm 0

3A2: Integrate their knowledge of 2, symmetry, and molecular formula (MF) with ¹3C NMR data and determine organic structure. Write a line-angle structure that is consistent with a MF of C7H10O and the ¹3C NMR data provided. You must label all the carbon atoms in your structure with the correct Roman letters (a, b, c, d, etc.) in the NMR data. ¹H Decoupled a b c 240 ppm d ef 0 240 DEPT 135° b c ppm 0 240 DEPT 90° b c ppm 0

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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3A2: Integrate their knowledge of 2, symmetry, and molecular formula (MF) with ¹3C NMR data and determine organic structure. Write a line-angle structure that is consistent with a MF of C7H10O and the 13C NMR data provided. You must label all the carbon atoms in your structure with the correct Roman letters (a, b, c, d, etc.) in the NMR data. ¹H Decoupled a b c b c ULILJAJ 0 240 ppm 240 ppm DEPT 135° d ef d DEPT 90° 0 240 b c ppm 0
Transcribed Image Text:3A2: Integrate their knowledge of 2, symmetry, and molecular formula (MF) with ¹3C NMR data and determine organic structure. Write a line-angle structure that is consistent with a MF of C7H10O and the 13C NMR data provided. You must label all the carbon atoms in your structure with the correct Roman letters (a, b, c, d, etc.) in the NMR data. ¹H Decoupled a b c b c ULILJAJ 0 240 ppm 240 ppm DEPT 135° d ef d DEPT 90° 0 240 b c ppm 0
Expert Solution
Step 1

The single carbon without hydrogens show a peak in 13C and no peak in DEPT.

The CH unit show positive peak in all 13C and DEPT-135 and DEPT-90.

The CH2 unit show positive peak in 13C, negative peak in DEPT-135 and no peak in DEPT-90.

The CH3 unit show positive peaks in each 13C and DEPT-135 but no peak in DEPT-90.

 

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