I need help with 3a and 3b. 605030line201053.5 57.5 61.5 65,5 69,5 73,5 77,5 81.5Exam ScoresRangeFrequencyBelow 61.512ctor61.5-65.53065.5-69.56969.5-73.55973.5-77.527Above 77.53The graph and table above show results from the same random sample of 200 exam scores. At a 10% Levelof Significance, test to see if the data fits a normal distribution with mean u = 69.5 and standarddeviation o = 4.To figure out the E column, use the Empirical Rule: (68% within one standard deviation, 95% within twostandard deviations, the rest beyond two standard deviations.Note: Even if you get E < 5, go ahead and proceed as usual; do not combine categories.1. The hypotheses are :O Ho:Exam scores are not normally distributedHa:Exam scores are normally distributedO Ho:Exam scores are normally distributedHa:Exam scores are not normally distributedkouənbas 2. This is aO leftO rightO two o tailed test; d.f. = 53a. The STS (to 2 decimals) is x?40.043b. The P-value (to 3 decimals) =4a. The decision at a = 10% isO Do not reject HoO Reject Ho4b. The conclusion isO There is insufficient evidence to conclude that Exam scores are normally distributedO There is sufficient evidence to conclude that Exam scores are not normally distributedO There is sufficient evidence to conclude that Exam scores are normally distributedO There is insufficient evidence to conclude that Exam scores are not normally distributed

Name: I need help with 3a and 3b. 605030line201053.5 57.5 61.5 65,5 69,5 73,
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Description: I need help with 3a and 3b. 605030line201053.5 57.5 61.5 65,5 69,5 73,5 77,5 81.5Exam ScoresRangeFrequencyBelow 61.512ctor61.5-65.53065.5-69.56969.5-73.55973.5-77.527Above 77.53The graph and table above show results from the same random sample of 200

Given: Categories Observed Expected proportions A 12 0.0228 B 30 0.1359 C 59 0.3413 D 69…

Answered: 3a. The STS (to 2 decimals) is x? =…

Math

Probability

3a. The STS (to 2 decimals) is x? = 40.04 3b. The P-value (to 3 decimals) =

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Concept explainers

Percentage

A percentage is a number indicated as a fraction of 100. It is a dimensionless number often expressed using the symbol %.

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Numbers are some measures used for counting. They can be compared one with another to know its position in the number line and determine which one is greater or lesser than the other.

Subtraction

Before we begin to understand the subtraction of algebraic expressions, we need to list out a few things that form the basis of algebra.

Addition

Before we begin to understand the addition of algebraic expressions, we need to list out a few things that form the basis of algebra.

Topic Video

Question

I need help with 3a and 3b.

60
50
30
line
20
10
53.5 57.5 61.5 65,5 69,5 73,5 77,5 81.5
Exam Scores
Range
Frequency
Below 61.5
12
ctor
61.5-65.5
30
65.5-69.5
69
69.5-73.5
59
73.5-77.5
27
Above 77.5
3
The graph and table above show results from the same random sample of 200 exam scores. At a 10% Level
of Significance, test to see if the data fits a normal distribution with mean u = 69.5 and standard
deviation o = 4.
To figure out the E column, use the Empirical Rule: (68% within one standard deviation, 95% within two
standard deviations, the rest beyond two standard deviations.
Note: Even if you get E < 5, go ahead and proceed as usual; do not combine categories.
1. The hypotheses are :
O Ho:Exam scores are not normally distributed
Ha:Exam scores are normally distributed
O Ho:Exam scores are normally distributed
Ha:Exam scores are not normally distributed
kouənbas

2. This is a
O leftO rightO two o tailed test; d.f. = 5
3a. The STS (to 2 decimals) is x?
40.04
3b. The P-value (to 3 decimals) =
4a. The decision at a = 10% is
O Do not reject Ho
O Reject Ho
4b. The conclusion is
O There is insufficient evidence to conclude that Exam scores are normally distributed
O There is sufficient evidence to conclude that Exam scores are not normally distributed
O There is sufficient evidence to conclude that Exam scores are normally distributed
O There is insufficient evidence to conclude that Exam scores are not normally distributed

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