3a) How many bytes of virtual memory are necessary to hold the entire array? By default , each entry in a array requires a Byte. Total virtual memory required = 256 256*8 B = 21*2 = 215 B = 2° KB = 32 KB 3b) How many pages are necessary to hold the entire array? Number of pages to hold the array = Virtual memory size / Page size. Putting the values in the above formula , the pages = 32 KB / 8 KB = 4 pages. %3D

Computer Networking: A Top-Down Approach (7th Edition)
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3c) Assuming an int requires 4 bytes, which elements of the array will start in physical memory?
• Considering the int required 4 B to store the value.
he element of the array which start in the physical location = Physical memory / Size of int.
Putting the values in the above formula , the element of the array which start in the physical
location = 1 MB / 4 B= 262144.
3d) Just considering virtual memory access time, how long will it take for function1() to execute?
3e) Just considering virtual memory access time, how long will it take for function2() to execute?
Remember to account for both read and write activity.
Transcribed Image Text:3c) Assuming an int requires 4 bytes, which elements of the array will start in physical memory? • Considering the int required 4 B to store the value. he element of the array which start in the physical location = Physical memory / Size of int. Putting the values in the above formula , the element of the array which start in the physical location = 1 MB / 4 B= 262144. 3d) Just considering virtual memory access time, how long will it take for function1() to execute? 3e) Just considering virtual memory access time, how long will it take for function2() to execute? Remember to account for both read and write activity.
3. Virtual memory
Study the two functions given below. Both use the same array declared as: static int data[256*256*8];
void function1()
{
int i;
int j;
for (i = 0; i< 32; i++)
for (j = 0; j< 256; j++)
data) = i;
}
void function2(0
{
int i;
int j;
for (i = 0; i< 32; i++)
for (j = 0; j< 256; j++)
dataj*2048] = i;
Assume the following behaviors in a virtual memory system. Reading or writing physical memory requires
50 nanoseconds. Reading or writing disk writing 10 milliseconds. Page size is 8 kilobytes. Presume that
the program has 1 megabyte of physical memory available. You may consider everything except the array
access itself to take no time. You should also assume that the first 1 megabyte of the array is in physical
memory initially. You may ignore any memory used by the program or stack to execute these functions.
Using this information, answer the following questions. In each case, show the work you use to calculate
the answer. Give your answer in a reasonable unit.
3a) How many bytes of virtual memory are necessary to hold the entire array?
By default , each entry in a array requires a Byte.
• Total virtual memory required = 256*256*8 B = 212*2 = 215 B = 25 KB = 32 KB
3b) How many pages are necessary to hold the entire array?
Number of pages to hold the array = Virtual memory size / Page size.
• Putting the values in the above formula , the pages = 32 KB / 8 KB = 4 pages.
Transcribed Image Text:3. Virtual memory Study the two functions given below. Both use the same array declared as: static int data[256*256*8]; void function1() { int i; int j; for (i = 0; i< 32; i++) for (j = 0; j< 256; j++) data) = i; } void function2(0 { int i; int j; for (i = 0; i< 32; i++) for (j = 0; j< 256; j++) dataj*2048] = i; Assume the following behaviors in a virtual memory system. Reading or writing physical memory requires 50 nanoseconds. Reading or writing disk writing 10 milliseconds. Page size is 8 kilobytes. Presume that the program has 1 megabyte of physical memory available. You may consider everything except the array access itself to take no time. You should also assume that the first 1 megabyte of the array is in physical memory initially. You may ignore any memory used by the program or stack to execute these functions. Using this information, answer the following questions. In each case, show the work you use to calculate the answer. Give your answer in a reasonable unit. 3a) How many bytes of virtual memory are necessary to hold the entire array? By default , each entry in a array requires a Byte. • Total virtual memory required = 256*256*8 B = 212*2 = 215 B = 25 KB = 32 KB 3b) How many pages are necessary to hold the entire array? Number of pages to hold the array = Virtual memory size / Page size. • Putting the values in the above formula , the pages = 32 KB / 8 KB = 4 pages.
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