393. lim x x → 0+ 1/x

Calculus: Early Transcendentals
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ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
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please solve 393 using L hospital rule

Chapter 4 | Applications of Derivatives
391.
392.
lim xex
x →∞
lim x
0+
X→
393. lim x
x → 0+
1/cos x
_0←x
1/x
394. lim (1-4)
395. lim (1-1)*
X→∞
Page <
Transcribed Image Text:Chapter 4 | Applications of Derivatives 391. 392. lim xex x →∞ lim x 0+ X→ 393. lim x x → 0+ 1/cos x _0←x 1/x 394. lim (1-4) 395. lim (1-1)* X→∞ Page <
Expert Solution
Step 1

Given: L=limx0+x1x.

To be find: evaluate the limit by using L hospital's rule.

Concept: according to L hospital's rule.

limx0fxgx is in 00 or intermediate form, then

limx0fxgx=limx0f'xg'x

Formulas used:

lnab=blna

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