39. Matching heights A stone is thrown with an initial velocity of 32 ft/s from the edge of a bridge that is 48 ft above the ground. The height of this stone above the ground t seconds after it is thrown is f(t)=-16t² +32t+48. If a second stone is thrown from the ground, then its height above the ground after t seconds is given by g(t)=-16t² + vot, where is the initial velocity of the second stone. Determine the value of Vo such that both stones reach the same high point. 0
39. Matching heights A stone is thrown with an initial velocity of 32 ft/s from the edge of a bridge that is 48 ft above the ground. The height of this stone above the ground t seconds after it is thrown is f(t)=-16t² +32t+48. If a second stone is thrown from the ground, then its height above the ground after t seconds is given by g(t)=-16t² + vot, where is the initial velocity of the second stone. Determine the value of Vo such that both stones reach the same high point. 0
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:39. Matching heights A stone is thrown with an initial
velocity of 32 ft/s from the edge of a bridge that is 48 ft above
the ground. The height of this stone above the ground t
seconds after it is thrown is f(t)=-16t² +32t+48. If a second
stone is thrown from the ground, then its height above the
ground after t seconds is given by g(t)=-16t² +vot, where is
the initial velocity of the second stone. Determine the value of
Vo such that both stones reach the same high point.
0
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