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= 3800 3c2 C3 6c3 — 3D 1200 -Зс, + 18с2 -4c1 - C2 - 12c3

= 3800 3c2 C3 6c3 — 3D 1200 -Зс, + 18с2 -4c1 - C2 - 12c3

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve this problem with the Jacobi's iteration method to ea = 5%.

= 3800 15c1 - 3c2 - C3 = -Зс, + 18с2 -4c1 — 3D 1200 6c3 — с2 — 12сз 3 2350
Transcribed Image Text:= 3800 15c1 - 3c2 - C3 = -Зс, + 18с2 -4c1 — 3D 1200 6c3 — с2 — 12сз 3 2350
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