38.2 m/s 5.50 m 50.0° A golfer hits an approach shot with a velocity of 38.2 m/s at 50 degrees above the horizontal. The golf ball lands directly next to the hole, 5.50 m above the ball's original position, and stops immediately. 8. How long was the ball in the air?
38.2 m/s 5.50 m 50.0° A golfer hits an approach shot with a velocity of 38.2 m/s at 50 degrees above the horizontal. The golf ball lands directly next to the hole, 5.50 m above the ball's original position, and stops immediately. 8. How long was the ball in the air?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Step 1
Given that,
The speed of a golfer, v = 38.2 m/s
It shot at an angle of 50 degrees above the horizontal.
The golf land directly next to the hole 5.5 m above the ball's original position.
We need to find the time for the ball in the air. We can use the second equation of kinematics to find it.
Where
is the vertical component of velocity
a = acceleration, a = -g (acceleration due to gravity)
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