38. A cup of coffee is sitting on a table in an airplane that is fly- ing at a constant altitude and a constant velocity. The coefficient of static friction between the cup and the table is 0.30. Suddenly, the plane accelerates, its altitude remaining constant. What is the maximum acceleration that the plane can have without the cup sliding backward on the table?

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**Problem 38:**

A cup of coffee is sitting on a table in an airplane that is flying at a constant altitude and a constant velocity. The coefficient of static friction between the cup and the table is 0.30. Suddenly, the plane accelerates, its altitude remaining constant. What is the maximum acceleration that the plane can have without the cup sliding backward on the table?

**Explanation:**

This problem involves calculating the maximum acceleration that the plane can experience while ensuring the cup remains stationary on the table, relying on the static friction between the cup and the table to prevent sliding. 

To solve:
- Use the formula for static friction: \( f_s = \mu_s \cdot N \)
- Here, \( \mu_s \) is the coefficient of static friction (0.30).
- \( N \) represents the normal force, which equals the gravitational force on the cup when the plane is flying level.
- The maximum static friction provides the force needed to accelerate the cup along with the plane.
- Set up the equation: \( f_s = m \cdot a \),
- Solving for \( a \), you get \( a = \mu_s \cdot g \) (where \( g \) is the acceleration due to gravity).

By substituting the known values, you can calculate the maximum acceleration \( a \).
Transcribed Image Text:**Problem 38:** A cup of coffee is sitting on a table in an airplane that is flying at a constant altitude and a constant velocity. The coefficient of static friction between the cup and the table is 0.30. Suddenly, the plane accelerates, its altitude remaining constant. What is the maximum acceleration that the plane can have without the cup sliding backward on the table? **Explanation:** This problem involves calculating the maximum acceleration that the plane can experience while ensuring the cup remains stationary on the table, relying on the static friction between the cup and the table to prevent sliding. To solve: - Use the formula for static friction: \( f_s = \mu_s \cdot N \) - Here, \( \mu_s \) is the coefficient of static friction (0.30). - \( N \) represents the normal force, which equals the gravitational force on the cup when the plane is flying level. - The maximum static friction provides the force needed to accelerate the cup along with the plane. - Set up the equation: \( f_s = m \cdot a \), - Solving for \( a \), you get \( a = \mu_s \cdot g \) (where \( g \) is the acceleration due to gravity). By substituting the known values, you can calculate the maximum acceleration \( a \).
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