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38. 39 The product of the roots of the quadratic equation 6x² - 17x - k = 0 is a. -15 b. 15 c. 14 d. -14 Divide 4 - 2x³5x² - 6x + 30 by (x - 5) What is the coefficient of ²2 What is the value of k?

38. 39 The product of the roots of the quadratic equation 6x² - 17x - k = 0 is a. -15 b. 15 c. 14 d. -14 Divide 4 - 2x³5x² - 6x + 30 by (x - 5) What is the coefficient of ²2 What is the value of k?

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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38. 39. 40. The product of the roots of the quadratic equation 6x² – 17x - k = 0 is -. What is the value of k? - a. -15 b. 15 c. 14 d. -14 Divide x4 - 2x³ - 5x² - 6x + 30 by (x - 5). What is the coefficient of x²? a. 1 c. 3 b. 2 d. 4 Find the value of x in the equation (x + yi)(1 − 2i) = 4i. a. -4/5 b. 3/5 c. -8/5 d. 4/5
Transcribed Image Text:38. 39. 40. The product of the roots of the quadratic equation 6x² – 17x - k = 0 is -. What is the value of k? - a. -15 b. 15 c. 14 d. -14 Divide x4 - 2x³ - 5x² - 6x + 30 by (x - 5). What is the coefficient of x²? a. 1 c. 3 b. 2 d. 4 Find the value of x in the equation (x + yi)(1 − 2i) = 4i. a. -4/5 b. 3/5 c. -8/5 d. 4/5
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38. 39. 40. The product of the roots of the quadratic equation 6x² – 17x - k = 0 is -. What is the value of k? - a. -15 b. 15 c. 14 d. -14 Divide x4 - 2x³ - 5x² - 6x + 30 by (x - 5). What is the coefficient of x²? a. 1 c. 3 b. 2 d. 4 Find the value of x in the equation (x + yi)(1 − 2i) = 4i. a. -4/5 b. 3/5 c. -8/5 d. 4/5
Transcribed Image Text:38. 39. 40. The product of the roots of the quadratic equation 6x² – 17x - k = 0 is -. What is the value of k? - a. -15 b. 15 c. 14 d. -14 Divide x4 - 2x³ - 5x² - 6x + 30 by (x - 5). What is the coefficient of x²? a. 1 c. 3 b. 2 d. 4 Find the value of x in the equation (x + yi)(1 − 2i) = 4i. a. -4/5 b. 3/5 c. -8/5 d. 4/5
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