36. Suppose a 5 x 6 matrix A has four pivot columns. Wha nullity A? Is Col A = R4? Why or why not?
36. Suppose a 5 x 6 matrix A has four pivot columns. Wha nullity A? Is Col A = R4? Why or why not?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:**Problem 36:**
Suppose a \(5 \times 6\) matrix \(A\) has four pivot columns. What is the nullity \(A\)? Is \(\text{Col} \, A = \mathbb{R}^4\)? Why or why not?
**Explanations:**
1. **Matrix and Dimensions:**
- The matrix \(A\) is a \(5 \times 6\) matrix, meaning it has 5 rows and 6 columns.
2. **Pivot Columns:**
- The matrix has four pivot columns, which are columns of the matrix that contain leading entries (or "pivots") in the row-reduced form of the matrix.
3. **Nullity of A:**
- Nullity is defined as the number of columns minus the rank of the matrix.
- Rank is the number of pivot columns, which is given as 4.
- Thus, nullity of \(A = \text{Number of columns} - \text{Rank} = 6 - 4 = 2\).
4. **Column Space:**
- \(\text{Col} \, A\) refers to the column space of \(A\), which is the set of all possible linear combinations of its column vectors.
- Since \(A\) is a \(5 \times 6\) matrix and has 4 pivot columns, the dimension of \(\text{Col} \, A\) is 4.
- However, \(\text{Col} \, A\) consists of vectors that are in \(\mathbb{R}^5\), not \(\mathbb{R}^4\), because the columns of \(A\) are 5-dimensional vectors.
Therefore, \(\text{Col} \, A\) cannot be equal to \(\mathbb{R}^4\). The column space \(\text{Col} \, A\) is actually a 4-dimensional subspace of \(\mathbb{R}^5\).
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