-36. Consider the following reaction having an equilibrium constant of 4.66 x 10-3 at a certain temperature: A(g) + B(g) = C(g) If 0.300 mol of A and 0.100 mol of B are mixed in a container and allowed to reach equilibrium, the concentrations of A= 0.300 – x and B=0.100 – x reaction that form the concentration of C = 2x are related to the equilibrium constant by the expression (2x)² (0.300 – x) (0.100 – x)' 4.66 x 10-3 = (a) Write the quadratic equation for x. (b) Solve the quadratic equation found in part (a) by completing the square and the quadratic formula. (c) Find the cquilibrium concentration AR and C
-36. Consider the following reaction having an equilibrium constant of 4.66 x 10-3 at a certain temperature: A(g) + B(g) = C(g) If 0.300 mol of A and 0.100 mol of B are mixed in a container and allowed to reach equilibrium, the concentrations of A= 0.300 – x and B=0.100 – x reaction that form the concentration of C = 2x are related to the equilibrium constant by the expression (2x)² (0.300 – x) (0.100 – x)' 4.66 x 10-3 = (a) Write the quadratic equation for x. (b) Solve the quadratic equation found in part (a) by completing the square and the quadratic formula. (c) Find the cquilibrium concentration AR and C
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section: Chapter Questions
Problem 18T
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Attached is a math question. Solve all parts with work shown!
![2-36. Consider the following reaction having
an equilibrium constant of 4.66 x 10-3
at a certain temperature:
A(g) + B(g) = C(g)
If 0.300 mol of A and 0.100 mol of B
are mixed in a container and allowed to
reach equilibrium, the concentrations
of A= 0.300 – x and B=0.100 – x
reaction that form the concentration of
C = 2x are related to the equilibrium
constant by the expression
(2x)²
4.66 x 10-3
(0.300 – x) (0.100 – x)'
(a) Write the quadratic equation for x.
(b) Solve the quadratic equation found
in part (a) by completing the square
and the quadratic formula.
(c) Find the equilibrium concentration
A, B, and C.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0309cbb4-3056-403b-8eb0-8f64136b6051%2F4453aa92-905c-4472-acbf-39ca2bdb7723%2F1vbjv2_processed.png&w=3840&q=75)
Transcribed Image Text:2-36. Consider the following reaction having
an equilibrium constant of 4.66 x 10-3
at a certain temperature:
A(g) + B(g) = C(g)
If 0.300 mol of A and 0.100 mol of B
are mixed in a container and allowed to
reach equilibrium, the concentrations
of A= 0.300 – x and B=0.100 – x
reaction that form the concentration of
C = 2x are related to the equilibrium
constant by the expression
(2x)²
4.66 x 10-3
(0.300 – x) (0.100 – x)'
(a) Write the quadratic equation for x.
(b) Solve the quadratic equation found
in part (a) by completing the square
and the quadratic formula.
(c) Find the equilibrium concentration
A, B, and C.
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