36 A- -[% 1)-[* ] -36 in the system x' = Ax; thus A is the negative of the matrix in Example 4. Once again we can solve the system using the principle of time reversal: Replacing t with -t in the right-hand side of the solution in Eq. (19) of Example 4 leads to x(t) = c1 35t + c2 -6

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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36
A- -[% 1)-[* ]
-36
in the system x' = Ax; thus A is the negative of the matrix in Example 4. Once again we can
solve the system using the principle of time reversal: Replacing t with -t in the right-hand
side of the solution in Eq. (19) of Example 4 leads to
x(t) = c1
35t + c2
-6
Transcribed Image Text:36 A- -[% 1)-[* ] -36 in the system x' = Ax; thus A is the negative of the matrix in Example 4. Once again we can solve the system using the principle of time reversal: Replacing t with -t in the right-hand side of the solution in Eq. (19) of Example 4 leads to x(t) = c1 35t + c2 -6
Expert Solution
Step 1

What is System of Differential Equation:

A set of finite differential equations is known as a system of differential equations in mathematics. Such a system can be either linear or non-linear. A system of partial differential equations or a system of ordinary differential equations can both be used to describe this one. Eigenvalues and eigenvectors are used to determine the solution. 

Given:

Given system is x'=Ax where A=--36-661=366-6-1.

To Determine:

We solve the system. 

Step 2

Given matrix is

A=--36-661=366-6-1

In order to determine the solution to the homogeneous system of differential equations x'=Ax, we need to determine the eigenvalues and corresponding eigenvectors of the matrix A.

The characteristic polynomial is

Pλ=36-λ6-6-1-λ=-36-λ1+λ+36=-36+35λ-λ2+36=λ2-35λ

Now, solve the characteristic equation Pλ=0. It follows, 

λ2-35λ=0λ=0,35

Therefore, two eigenvalues are λ1=0, λ2=35.

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