35.4527 70.9054 3. How many moles are in 3.28 grams of Calcium Chloride (CaCl) Grams to Moles: Given: 3.78 Gad! 40.078 + 70.9054 l10.9034 p.oz95 m Find: m 3.789 IM Given: Find: 110.9734

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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35.4527
70.9054
Grams to Moles:
3. How many moles are in 3.28 grams of Calcium Chloride (CaCl)
니0.078
+ 70.9054
110.9034
p.oz95 m
Given: 3. 78 Jai!
Find: 7m
3.289
IM
Given:
(10.9834
Find:
Grams to Grams: Remember these equations use mole to mole ratio:
4. How many grams of butane, C,H10, are needed to make 108 grams of CO,?
C,H10 +50-4 HO +,
5Y.433
Given: 08 9 Cor
117.866
Find: 7 I Lu Hio
3g co cutlio
S$ 3.597
Mole Ratio: CyHio
3 53.548
Itoz
Mole Ratio: 3 02
Transcribed Image Text:35.4527 70.9054 Grams to Moles: 3. How many moles are in 3.28 grams of Calcium Chloride (CaCl) 니0.078 + 70.9054 110.9034 p.oz95 m Given: 3. 78 Jai! Find: 7m 3.289 IM Given: (10.9834 Find: Grams to Grams: Remember these equations use mole to mole ratio: 4. How many grams of butane, C,H10, are needed to make 108 grams of CO,? C,H10 +50-4 HO +, 5Y.433 Given: 08 9 Cor 117.866 Find: 7 I Lu Hio 3g co cutlio S$ 3.597 Mole Ratio: CyHio 3 53.548 Itoz Mole Ratio: 3 02
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