34. A student was asked to determine the molar enthalpy of solution of potassium hydroxide. She poured 100 g of water into an insulated cup and recorded the temperature of the water. She then added 2.00 g of KOH(s) to the water, stirred the solution, and recorded the highest temperature reached. Her analysis of the data resulted in an answer of -46 kJ/mol. If the student had used 4.00 g of KOH(s), the O temperature change would double and the molar heat of reaction would double heat released would be the same but the moles of KOH would double heat released would double but the molar heat of reaction would remain the same temperature would double and, because the mass of KOH had doubled, the molar heat of reaction would be four times as great
34. A student was asked to determine the molar enthalpy of solution of potassium hydroxide. She poured 100 g of water into an insulated cup and recorded the temperature of the water. She then added 2.00 g of KOH(s) to the water, stirred the solution, and recorded the highest temperature reached. Her analysis of the data resulted in an answer of -46 kJ/mol. If the student had used 4.00 g of KOH(s), the O temperature change would double and the molar heat of reaction would double heat released would be the same but the moles of KOH would double heat released would double but the molar heat of reaction would remain the same temperature would double and, because the mass of KOH had doubled, the molar heat of reaction would be four times as great
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:34. A student was asked to determine the molar enthalpy of solution
of potassium hydroxide. She poured 100 g of water into an insulated cup
and recorded the temperature of the water. She then added 2.00 g of
KOH(s) to the water, stirred the solution, and recorded the highest
temperature reached. Her analysis of the data resulted in an answer of -46
kJ/mol. If the student had used 4.00 g of KOH(s), the
O temperature change would double and the molar heat of reaction would double
heat released would be the same but the moles of KOH would double
heat released would double but the molar heat of reaction would remain the same
temperature would double and, because the mass of KOH had doubled, the molar
heat of reaction would be four times as great
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