34 A Sled of mass =6.50 ke s Shay slope is shd hill that hes oloun A Sled mass =6.50 Snow-Couered 45,0 dleprees The is pushige an applied fre olown on the Sled prepedicular the in cline el 80.4 N. The coefficiant of kenetic Snow kamekic g fachian. betueen the sled and is 0,100. which g he free boody diaproms below is for she sidu hon above? FA drow ocrectly FK FK FK
34 A Sled of mass =6.50 ke s Shay slope is shd hill that hes oloun A Sled mass =6.50 Snow-Couered 45,0 dleprees The is pushige an applied fre olown on the Sled prepedicular the in cline el 80.4 N. The coefficiant of kenetic Snow kamekic g fachian. betueen the sled and is 0,100. which g he free boody diaproms below is for she sidu hon above? FA drow ocrectly FK FK FK
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Transcribed Image Text:34
A Sled of
mass =6.50 kp
hill thet
45,0deprees. The is
olown
is slay slape
has
applied fre
prepedicular
Snow-Couered
an
Sled
incline e 80.4 N. The cooficiant f
kanedic faction behuren dehe sled aua
olown on the
to
pushig,
She!
Snow
is
0,100.
which he free booly diaprous below is
drow forrectly for the sidere hnon above?
Su
个
Fx
FA
FA
m2
Expert Solution
Step 1
Sled is going down so friction will act upwards parallel to incline. Weigh of sled will act vertically downward. Applied force is perpendicular to incline and downward. Normal force will be perpendicular and upward.
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