33. If a first order system and its time response to a unit step are as shown below, the gain K is: Explanation: Y(s)/R(s)3K/1+sT+K By use of partial fraction, K/T/s+(K+1/T) Taking inverse Laplace transform on both the sides Y(t)=K/K+1[1-e^(K+1/T)t) K=4 r(t) y(t) K/1+sT a) 0.25 b) 0.8 c) 1 d) 4 0.8

Introductory Circuit Analysis (13th Edition)
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33. If a first order system and its time response to a unit step are as shown
below, the gain K is:
Explanation: Y(s)/R(s)%3DK/1+sT+K
By use of partial fraction, K/T/s+(K+1/T)
Taking inverse Laplace transform on both the sides
Y(t)=K/K+1[1-e^(K+1/T)t) K=4
r(t)
y(t)
K/1+sT
a) 0.25
b) 0.8
c) 1
d) 4
0.8-
34. The unit impulse response of a system having transfer function K/(s+a) is shown below. The value of
a is
Explanation: G(s) K/s+a
C(s) =K/(s+a) Since R(s) =1
C(t) =Ke^-at
T=1/a
Exponential Decrease
C(t) =0.37K
T= t2=1/a.
a) t1
b) t2
c) 1/t1
d) 1/12
0.63 K
0.37 K
2
Transcribed Image Text:33. If a first order system and its time response to a unit step are as shown below, the gain K is: Explanation: Y(s)/R(s)%3DK/1+sT+K By use of partial fraction, K/T/s+(K+1/T) Taking inverse Laplace transform on both the sides Y(t)=K/K+1[1-e^(K+1/T)t) K=4 r(t) y(t) K/1+sT a) 0.25 b) 0.8 c) 1 d) 4 0.8- 34. The unit impulse response of a system having transfer function K/(s+a) is shown below. The value of a is Explanation: G(s) K/s+a C(s) =K/(s+a) Since R(s) =1 C(t) =Ke^-at T=1/a Exponential Decrease C(t) =0.37K T= t2=1/a. a) t1 b) t2 c) 1/t1 d) 1/12 0.63 K 0.37 K 2
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