33. Find the directrix. (y- 9)2 - 8 O y = -9 O y = -7 O x = -7 | x = -9

Algebra and Trigonometry (6th Edition)
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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Problem 33: Find the Directrix**

Given the equation of a parabola:

\[ x = \frac{1}{4}(y - 9)^2 - 8 \]

Determine the directrix from the following options:

- \( \circ \; y = -9 \)
- \( \circ \; y = -7 \)
- \( \circ \; x = -7 \)
- \( \circ \; x = -9 \)

**Explanation:**

The equation provided is in vertex form for a parabola that opens horizontally. The general form for such a parabola is:

\[ x = a(y - k)^2 + h \]

Where \((h, k)\) is the vertex of the parabola. In this case, the vertex is \((-8, 9)\).

This specific parabola has \(a = \frac{1}{4}\), which informs us about the direction and width of the parabola's opening. For a horizontally opening parabola, the directrix is a vertical line given by the equation:

\[ x = h - \frac{1}{4a} \]

Substituting the values:

\[ x = -8 - \frac{1}{4 \times \frac{1}{4}} \]
\[ x = -8 - 1 \]
\[ x = -9 \]

Therefore, the directrix is \(x = -9\).
Transcribed Image Text:**Problem 33: Find the Directrix** Given the equation of a parabola: \[ x = \frac{1}{4}(y - 9)^2 - 8 \] Determine the directrix from the following options: - \( \circ \; y = -9 \) - \( \circ \; y = -7 \) - \( \circ \; x = -7 \) - \( \circ \; x = -9 \) **Explanation:** The equation provided is in vertex form for a parabola that opens horizontally. The general form for such a parabola is: \[ x = a(y - k)^2 + h \] Where \((h, k)\) is the vertex of the parabola. In this case, the vertex is \((-8, 9)\). This specific parabola has \(a = \frac{1}{4}\), which informs us about the direction and width of the parabola's opening. For a horizontally opening parabola, the directrix is a vertical line given by the equation: \[ x = h - \frac{1}{4a} \] Substituting the values: \[ x = -8 - \frac{1}{4 \times \frac{1}{4}} \] \[ x = -8 - 1 \] \[ x = -9 \] Therefore, the directrix is \(x = -9\).
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