33. A trapper walks a 5.0-km straight-line distance from his cabin to the lake, as shown in the following figure. Use a graphical method (the parallelogram rule) to determine the trapper's displacement directly to the east and displacement directly to the north that sum up to his resultant displacement vector. If the trapper walked only in directions east and north, zigzagging his way to the lake, how many kilometers would he have to walk to get to the lake? Path 2 S= 5.0 km Path 1 40°

College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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33. A trapper walks a 5.0-km straight-line distance from
his cabin to the lake, as shown in the following figure. Use
a graphical method (the parallelogram rule) to determine
the trapper's displacement directly to the east and
displacement directly to the north that sum up to his
resultant displacement vector. If the trapper walked only in
directions east and north, zigzagging his way to the lake,
how many kilometers would he have to walk to get to the
lake?
Path 2
S= 5.0 km
Path 1
40°
Transcribed Image Text:33. A trapper walks a 5.0-km straight-line distance from his cabin to the lake, as shown in the following figure. Use a graphical method (the parallelogram rule) to determine the trapper's displacement directly to the east and displacement directly to the north that sum up to his resultant displacement vector. If the trapper walked only in directions east and north, zigzagging his way to the lake, how many kilometers would he have to walk to get to the lake? Path 2 S= 5.0 km Path 1 40°
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